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jekas [21]
2 years ago
10

Translate the phrase into algebraic symbols. the sum of a number y and sixteen.

Mathematics
1 answer:
jarptica [38.1K]2 years ago
3 0
The answer to this is y+16
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What is the value of cosθ given that (−2, −3) is a point on the terminal side of θ ?
snow_tiger [21]

Answer:

-0.555

Step-by-step explanation:

The terminal point of the vector in this problem is

(-2,-3)

So, it is in the 3rd quadrant.

We want to find the angle \theta that gives the direction of this vector.

We can write the components of the vector along the x- and y- direction as:

v_x = -2\\v_y = -3

The tangent of the angle will be equal to the ratio between the y-component and the x-component, so:

tan \theta = \frac{v_y}{v_x}=\frac{-3}{-2}=1.5\\\theta=tan^{-1}(1.5)=56.3^{\circ}

However, since we are in the 3rd quadrant, the actual angle is:

\theta=180^{\circ} + 56.3^{\circ} = 236.3^{\circ}

So now we can find the cosine of the angle, which will be negative:

cos \theta = cos(236.3^{\circ})=-0.555

7 0
2 years ago
I need help!
artcher [175]
Set the function equal to 2065 and solve for g, then that answer is how many games he played
4 0
2 years ago
Read 2 more answers
What is the solution set of {x | x < -3} ∩ {x | x > 5}
lozanna [386]
Any x in this set will be real numbers that are both less than -3 and greater than 5. But that's not possible, so this set is empty.
7 0
3 years ago
twice the sum of a number and 2 is equal to three times the difference of the number and 3. Find the number
Lana71 [14]
2(x+2)=3(x-3)
2x+4=3x-9
2x=3x-13
-x=-13
x=13

The number is 13
3 0
3 years ago
-5/6x-7/30x+1/5x-52 please help me guys cuz imk not good with math
Marina CMI [18]

Answer:

\frac{-13}{15} x-52

Step-by-step explanation:

\frac{-5}{6}x-\frac{7}{30}x+\frac{1}{5}x-52

=\frac{-5}{6}x+\frac{-7}{30}x+\frac{1}{5}x+-52

Combine Like Terms:

=\frac{-5}{6}x+\frac{-7}{30}x+\frac{1}{5}x+-52

=(\frac{-5}{6}x+\frac{-7}{30}x+\frac{1}{5}x)+(-52)

=\frac{-13}{15}x+-52

Therefore, \frac{-13}{15}x+-52 will be your final answer.

7 0
2 years ago
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