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Brums [2.3K]
2 years ago
15

James has a mass of 98 kg and Basma has a mass of 59 kg. James is running at 3.0 m/s, while Basma is running at 4.0 m/s.

Physics
1 answer:
masha68 [24]2 years ago
4 0

(a) James has the most momentum which is 294 kgm/s.

(b) The resultant force acting on Basma is 90.78 N.

(c) The time taken for James to stop is 3.2 seconds.

<h3>Momentum of each person</h3>

Momentum of James: P = mv = 98 x 3 = 294 kgm/s

Momentum of Basma: P = mv = 59 x 4 = 236 kgm/s

<h3>Resultant force of Basma</h3>

F = ma = mv/t = P/t = 236/2.6 = 90.78 N

<h3>Time for James to stop</h3>

F = P/t

t = P/F

t = 294/90.78

t = 3.2 s

Learn more about momentum here: brainly.com/question/7538238

#SPJ1

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you can build a mote around your castle and put crocodiles in it.

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How much heat will be needed to warm 187 grams of water from 10 0C to 90 0C?
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<h3>Hello there!</h3>

Here, you are looking for the amount of heat put in for water, at a mass of 187 grams, to change by 80 degrees.

The equation commonly accepted to find the answer to questions like these is the specific heat formula.

The equation is Q = mc∆T, where Q is the amount of energy put in to raise the temperature by a certain amount, m is the mass, c is the specific heat capacity, and ΔT is the amount of temperature change.

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m = 187 grams

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The kinetic energy of a book on a shelf is equal to the work done to lift the book to the shelf. t/f
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A subway train starts from rest at a station and accelerates at a rate of 1.68 m/s2 for 14.2 s. It runs at constant speed for 68
liubo4ka [24]

Answer:

total distance = 1868.478 m

Explanation:

given data

accelerate = 1.68 m/s²

time = 14.2 s

constant time = 68 s

speed = 3.70 m/s²

to find out

total distance

solution

we know train start at rest so final velocity will be after 14 .2 s is

velocity final = acceleration × time      ..............1

final velocity = 1.68 × 14.2

final velocity = 23.856 m/s²

and for stop train we need time that is

final velocity = u + at

23.856 = 0 + 3.70(t)

t = 6.44 s

and

distance = ut + 1/2 × at²     ...........2

here u is initial velocity and t is time for 14.2 sec

distance 1 = 0 + 1/2 × 1.68 (14.2)²

distance 1 = 169.37 m

and

distance for 68 sec

distance 2= final velocity × time

distance 2= 23.856 × 68

distance 2 = 1622.208 m

and

distance for 6.44 sec

distance 3 = ut + 1/2 × at²

distance 3 = 23.856(6.44) - 0.5 (3.70) (6.44)²

distance 3 = 76.90 m

so

total distance = distance 1 + distance 2 + distance 3

total distance = 169.37 + 1622.208 + 76.90

total distance = 1868.478 m

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