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1 year ago

James has a mass of 98 kg and Basma has a mass of 59 kg. James is running at 3.0 m/s, while Basma is running at 4.0 m/s.

Physics

1 answer:

masha68 [24]1 year ago

4 0

(a) James has the most momentum which is 294 kgm/s.

(b) The resultant force acting on Basma is 90.78 N.

<h3>Momentum of each person</h3>

Momentum of James: P = mv = 98 x 3 = 294 kgm/s

Momentum of Basma: P = mv = 59 x 4 = 236 kgm/s

<h3>Resultant force of Basma</h3>

F = ma = mv/t = P/t = 236/2.6 = 90.78 N

<h3>Time for James to stop</h3>

F = P/t

t = P/F

t = 294/90.78

t = 3.2 s

Learn more about momentum here: brainly.com/question/7538238

#SPJ1

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IRINA_888 [86]

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2 years ago

You shake a bottle of soda and take off the cap. If the soda shoots out of the

kicyunya [14]

Answer:

A. 11.5 m

Explanation:

Given,

The initial velocity of the soda cap, u = 15 m/s

The soda bottle cap is projected vertically upwards,

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The maximum height of the projectile is given by the formula,

$h_{max} =\frac{u^{2}sin^{2}\phi}{2g}$

Substituting the given values in the above equation

$h_{max} =\frac{15^{2}sin^{2}90}{2X9.8}$

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2 years ago

he fan blades on a jet engine make one thousand revolutions in a time of 54.9 ms. What is the angular frequency of the blades?

Gnesinka [82]

So, the angular frequency of the blades approximately <u>36.43π rad/s</u>.

<h3>Introduction</h3>

Hi ! Here I will discuss about the angular frequency or what is also often called the angular velocity because it has the same unit dimensions. <u>Angular frequency occurs, when an object vibrates (either moving harmoniously / oscillating or moving in a circle)</u>. Angular frequency can be roughly interpreted as the magnitude of the change in angle (in units of rad) per unit time. So, based on this understanding, the angular frequency can be calculated using the equation :

$\boxed{\sf{\bold{\omega = \frac{\theta}{t}}}}$

With the following condition :

$\sf{\omega}$ = angular frequency (rad/s)
$\sf{\theta}$ = change of angle value (rad)
t = interval of the time (s)

<h3>Problem Solving</h3>

We know that :

$\sf{\theta}$ = change of angle value = 1,000 revolution = 1,000 × 2π rad = 2,000π rad/s >> Remember 1 rev = 2π rad/s.
t = interval of the time = 54.9 s.

What was asked :

$\sf{\omega}$ = angular frequency = ... rad/s

Step by step :

$\sf{\omega = \frac{\theta}{t}}$

$\sf{\omega = \frac{2,000 \pi}{54.9}}$

$\boxed{\sf{\omega \approx 36.43 \pi \: rad/s}}$

<h3>Conclusion :</h3>

So, the angular frequency of the blades approximately 36.43π rad/s.

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