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liubo4ka [24]
3 years ago
15

An element emits a spectrum that____________.a)is evenly spaced.b)is the same as all other elements.c)is unique to that element.

d)is indistinguishable from most other elements.e)is evenly spaced and unique to that element.
Physics
1 answer:
Fittoniya [83]3 years ago
5 0

Answer:

c)is unique to that element

Explanation:

 The spectrum emitted by a element shows the internal electronic structure of that element.We know that all element is having different internal electronic structure that is why all element emits different spectrum.And the spacing between the spectrum is uneven .

Therefore the answer will be option C.

c)is unique to that element

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18. An electric dipole is completely inside a closed imaginary surface and there are no other charges. True or false: (a) The el
Zina [86]

Answer:

Explanation:

We shall apply Gauss's theorem to calculate the electric flux through a closed surface due to charge contained in side

Total charge inside surface = zero  

So total electric flux through closed surface will be zero.  

or electric flux going out = electric flux coming in  

(a) The electric field is zero everywhere on the surface.  True  

(b) The electric field is normal to the surface everywhere on the surface. - false

(c) The electric flux through the surface is zero. True  

(d) The electric flux through the surface could be positive or negative - false

(e) The electric flux through a portion of the surface might not be zero - True

6 0
3 years ago
Brainliest if correct
ozzi

Answer:

It's is c coz the weight is equal to the normal force

7 0
3 years ago
A charge of −20 µC is distributed uniformly over the surface of a spherical conductor of radius 11.0 cm. Determine the electric
Alex73 [517]

Answer:

(a) -6.76\times 10^{12}\ N/C

(b) -1.352\times 10^{13}\ N/C

(c) -7.2\times 10^{11}\ N/C

Explanation:

(a)

Given:

Charge on sphere (Q) = -20\ \mu C=-20\times 10^{-6}\ C

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 5 cm = 0.05 m

Coulomb's constant (k) = 9\times 10^{9}\ Nm^2/C^2

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r ≤ R' from the center of sphere is given as:

E=(\frac{kQ}{R^3})r

Plug in the given values and solve for 'E'. This gives,

E_{in}=(\frac{9\times 10^{9}\times -20}{(0.110)^3})\times 0.05\\\\E_{in}=-1.352\times 10^{14}\times 0.05\\\\E_{in}=-6.76\times 10^{12}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)

(b)

Given:

Charge on sphere (Q) = -20\ \mu C=-20\times 10^{-6}\ C

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 10 cm = 0.10 m

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r ≤ R' from the center of sphere is given as:

E=(\frac{kQ}{R^3})r

Plug in the given values and solve for 'E'. This gives,

E_{in}=(\frac{9\times 10^{9}\times -20}{(0.110)^3})\times 0.10\\\\E_{in}=-1.352\times 10^{14}\times 0.10\\\\E_{in}=-1.352\times 10^{13}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)

(c)

Given:

Charge on sphere (Q) = -20\ \mu C=-20\times 10^{-6}\ C

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 50 cm = 0.50 m

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r > R' from the center of sphere is given as:

E=\dfrac{kQ}{r^2}

Plug in the given values and solve for 'E'. This gives,

E_{out}=(\frac{9\times 10^{9}\times -20}{(0.50)^2})\\\\E_{out}=-7.2\times 10^{11}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)

8 0
4 years ago
How could a homework machine help students all around the world?
slamgirl [31]

Answer:

Hello There!!

Explanation:

The machine can help you alot and do all your homework while you rest and let the homework machine do it and get good grades because of it with no worries but if the machine does it then you won't learn how to do them.

hope this helps,have a great day!!

~Pinky~

8 0
3 years ago
Yusef is doing an experiment to find out how the amount of sunlight affects the growth of a seedling what is the variable in yis
Mekhanik [1.2K]

Answer:

Independent Variable: Amount of Sunlight

Dependent Variable: Growth of Seedling

Constant: Things that don't change like kind of soil, type of pot, amount of water, etc.

Explanation:

I'm not sure which variable (independent, dependent, etc) so I'm going to do them all

7 0
3 years ago
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