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Inessa [10]
2 years ago
15

Suppose a free-fall ride at an amusement park starts at rest and Is In free fall.

Physics
2 answers:
Fittoniya [83]2 years ago
4 0
Ella has both dimes (d) and nickels (n) in her piggy bank. She has a total of 36 coins in all, and has 4 more dimes than nickels. Find how much money she has in her piggy bank using a two-variable, two-equation system.

Ella has both dimes (d) and nickels (n) in her piggy bank. She has a total of 36 coins in all, and has 4 more dimes than nickels. Find how much money she has in her piggy bank using a two-variable, two-equation system.
jasenka [17]2 years ago
3 0

Answer: 22.54 m/s and 25.921 meters

Explanation:

hey dog have you ever heard of these cool equations..

v=v_{o} + at

dude what DOES THIS MEAN??? ok ill tell you. velocity equals initial velocity plus acceleration times time.    uhh... interesting.... hmm...

lets do some substitution...

we know that a means acceleration and gravity is a type of acceleration. ok?

v = 0 + (9.8)(2.3)

remember I PUT THE ZERO THERE BECAUSE IT STARTED AT REST

22.54 is the velocity

now for b. look at THIS COOL NEW EQUATION

delta Y =  \frac{1}{2}at^{2} + v_{o}t

ok so i put delta Y but it can also be delta X it just means displacement... i put delta Y because these kids are falling straight down in a rollercoaster like space mountain or something... ok lets do some replacing am i right?...

\frac{1}{2}(9.8)(2.3^{2}) + 0(2.3)

LISTEN! forget about the zero times 2.3 its just gonna be zero anyways.

so lets calculate... and we get 25.921 meters (or if you want to round to 2 sig figs then its 26 meters)

have a swag day

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Answer:

Any incident ray traveling parallel to the principal axis of a converging lens will refract through the lens and travel through the focal point on the opposite side of the lens. ... These rays of light will refract when they enter the lens and refract when they leave the lens.

Hope this helps...

7 0
2 years ago
When two objects with electrical charges interact, which affect the strength of that interaction?
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6 0
3 years ago
Please help on this one?
kupik [55]

Answer: A)30V. First find the current of the circuit. I=V/R(total resistance). So I=60/120=0.5. Now to find voltage drop in R3 use ohms law as given. V(of 3)=(0.5)(60)=30V

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2 years ago
When an electric current flows through a long conductor, each free electron moves
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7 0
3 years ago
A small rubber ball is launched by a compressed-air cannon from ground level with an initial speed of 11.8 m/s directly upward.
Fantom [35]

Answer:

7.09683 m

1.20285 s

2.4057 s

11.8 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² (negative up, positive down)

From equation of motion we have

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-11.8^2}{2\times -9.81}\\\Rightarrow s=7.09683\ m

The maximum height above the ground that the ball reaches is 7.09683 m

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-11.8}{-9.81}\\\Rightarrow t=1.20285\ s

Time taken to go up is 1.20285 s it will take the same time to come down so total time taken to reach the ground after it is shot is 1.20285+1.20285 = 2.4057 s

v=u+at\\\Rightarrow v=0+9.81\times 1.20285\\\Rightarrow v=11.8\ m/s

The velocity just before it hits the ground is 11.8 m/s

6 0
2 years ago
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