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Inessa [10]
3 years ago
15

Suppose a free-fall ride at an amusement park starts at rest and Is In free fall.

Physics
2 answers:
Fittoniya [83]3 years ago
4 0
Ella has both dimes (d) and nickels (n) in her piggy bank. She has a total of 36 coins in all, and has 4 more dimes than nickels. Find how much money she has in her piggy bank using a two-variable, two-equation system.

Ella has both dimes (d) and nickels (n) in her piggy bank. She has a total of 36 coins in all, and has 4 more dimes than nickels. Find how much money she has in her piggy bank using a two-variable, two-equation system.
jasenka [17]3 years ago
3 0

Answer: 22.54 m/s and 25.921 meters

Explanation:

hey dog have you ever heard of these cool equations..

v=v_{o} + at

dude what DOES THIS MEAN??? ok ill tell you. velocity equals initial velocity plus acceleration times time.    uhh... interesting.... hmm...

lets do some substitution...

we know that a means acceleration and gravity is a type of acceleration. ok?

v = 0 + (9.8)(2.3)

remember I PUT THE ZERO THERE BECAUSE IT STARTED AT REST

22.54 is the velocity

now for b. look at THIS COOL NEW EQUATION

delta Y =  \frac{1}{2}at^{2} + v_{o}t

ok so i put delta Y but it can also be delta X it just means displacement... i put delta Y because these kids are falling straight down in a rollercoaster like space mountain or something... ok lets do some replacing am i right?...

\frac{1}{2}(9.8)(2.3^{2}) + 0(2.3)

LISTEN! forget about the zero times 2.3 its just gonna be zero anyways.

so lets calculate... and we get 25.921 meters (or if you want to round to 2 sig figs then its 26 meters)

have a swag day

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Condensation can also produce water droplets on the outside of soda cans or glasses of cold water. When warm air hits the cold surface, it reaches its dew point and condenses. This leaves droplets of water on the glass or can.

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4 0
3 years ago
An air bubble at the bottom of a lake 36.0 m deep has a volume of 1.22 cm^3. If the temperature at the bottom is 5.9°C and at th
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Answer:

volume of the bubble just before it reaches the surface is 5.71 cm³

Explanation:

given data

depth h = 36 m

volume v2 = 1.22 cm³ = 1.22 × 10^{-6} m³

temperature bottom t2 = 5.9°C = 278.9 K

temperature top  t1 = 16.0°C = 289 K

to find out

what is the volume of the bubble just before it reaches the surface

solution

we know at top atmospheric pressure is about P1 = 10^{5} Pa

so pressure at bottom P2 = pressure at top + ρ×g×h

here ρ is density and h is height and g is 9.8 m/s²

so

pressure at bottom P2 = 10^{5} + 1000 × 9.8 ×36

pressure at bottom P2 =4.52 × 10^{5}  Pa

so from gas law

\frac{P1*V1}{t1} = \frac{P2*V2}{t2}

here p is pressure and v is volume and t is temperature

so put here value and find v1

\frac{10^{5}*V1}{289} = \frac{4.52*10^{5}*1.22}{278.9}

V1 = 5.71 cm³

volume of the bubble just before it reaches the surface is 5.71 cm³

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