Ask question

Ask question

All categories

3 years ago

15

Suppose a free-fall ride at an amusement park starts at rest and Is In free fall.

2 answers:

Fittoniya [83]3 years ago

4 0

Ella has both dimes (d) and nickels (n) in her piggy bank. She has a total of 36 coins in all, and has 4 more dimes than nickels. Find how much money she has in her piggy bank using a two-variable, two-equation system.

Ella has both dimes (d) and nickels (n) in her piggy bank. She has a total of 36 coins in all, and has 4 more dimes than nickels. Find how much money she has in her piggy bank using a two-variable, two-equation system.

jasenka [17]3 years ago

3 0

Answer: 22.54 m/s and 25.921 meters

Explanation:

hey dog have you ever heard of these cool equations..

$v=v_{o} + at$

dude what DOES THIS MEAN??? ok ill tell you. velocity equals initial velocity plus acceleration times time. uhh... interesting.... hmm...

lets do some substitution...

we know that a means acceleration and gravity is a type of acceleration. ok?

$v = 0 + (9.8)(2.3)$

remember I PUT THE ZERO THERE BECAUSE IT STARTED AT REST

22.54 is the velocity

now for b. look at THIS COOL NEW EQUATION

$delta Y = \frac{1}{2}at^{2} + v_{o}t$

ok so i put delta Y but it can also be delta X it just means displacement... i put delta Y because these kids are falling straight down in a rollercoaster like space mountain or something... ok lets do some replacing am i right?...

$\frac{1}{2}(9.8)(2.3^{2}) + 0(2.3)$

LISTEN! forget about the zero times 2.3 its just gonna be zero anyways.

so lets calculate... and we get 25.921 meters (or if you want to round to 2 sig figs then its 26 meters)

have a swag day

You might be interested in

irakobra [83]

Answer:

SECOND LAW OF NEWTON

Explanation:

When the rocket fires the engines the gases leave at high speed and collide with the space station, transferring an impulse given by the expression

I = F t = Δp

As we can see this expression is a form of Newton's second law

F = m a

a = dv / dt

F = m dv / dt

F dt = m dv

p = mv

F dt = dp

Therefore the station moves through the SECOND LAW OF NEWTON

7 0

3 years ago

Distance meters Time (seconds) Trial Tria 2 Trials Average 3 053 059 0.52 055 6 106 719 104 Uning the values trom the data table

kumpel [21]

Jsisisusuagahannananana this is worth 22 points g that’s crazy 25

5 0

2 years ago

What happens to the water after it goes<br> down the drain?

valentina_108 [34]

Answer:

, it flows through your community's sanitary sewer system to a wastewater treatment facility.

6 0

3 years ago

The two types of vitamins are fat and water soluble?

lianna [129]

Its true hopefully this helps you.

4 0

3 years ago

Suppose that a planet were discovered between the sun and Mercury, with a circular orbit of radius equal to 2/3 of the average o

Musya8 [376]

Explanation:

It is given that,

A planet were discovered between the sun and Mercury, with a circular orbit of radius equal to 2/3 of the average orbit radius of Mercury.

Mass of the Sun, $M=1.99\times 10^{30}\ kg$

Radius of Mercury's orbit, $r=5.79\times 10^{10}\ m$

Radius of discovered planet, $R=\dfrac{2}{3}r$

$R=\dfrac{2}{3}\times 5.79\times 10^{10}\ m=3.86\times 10^{10}\ m$

Let T is the orbital period of such a planet. Using Kepler's third law of planetary motion as :

$T^2\propto R^3$

$T^2=\dfrac{4\pi^2R^3}{GM}$

$T^2=\dfrac{4\pi^2\times (3.86\times 10^{10})^3}{6.67\times 10^{-11}\times 1.99\times 10^{30}}$

$T=\sqrt{1.71\times 10^{13}}$

T = 4135214.625 s

or

T = 47.86 days

So, the orbital period of such a planet is 47.86 days. Hence, this is the required solution.

6 0

3 years ago