Suppose a free-fall ride at an amusement park starts at rest and Is In free fall.

2 answers:

4 0

Ella has both dimes (d) and nickels (n) in her piggy bank. She has a total of 36 coins in all, and has 4 more dimes than nickels. Find how much money she has in her piggy bank using a two-variable, two-equation system.

Ella has both dimes (d) and nickels (n) in her piggy bank. She has a total of 36 coins in all, and has 4 more dimes than nickels. Find how much money she has in her piggy bank using a two-variable, two-equation system.

jasenka [17]3 years ago

3 0

Answer: 22.54 m/s and 25.921 meters

Explanation:

hey dog have you ever heard of these cool equations..

$v=v_{o} + at$

dude what DOES THIS MEAN??? ok ill tell you. velocity equals initial velocity plus acceleration times time. uhh... interesting.... hmm...

lets do some substitution...

we know that a means acceleration and gravity is a type of acceleration. ok?

$v = 0 + (9.8)(2.3)$

remember I PUT THE ZERO THERE BECAUSE IT STARTED AT REST

22.54 is the velocity

now for b. look at THIS COOL NEW EQUATION

$delta Y = \frac{1}{2}at^{2} + v_{o}t$

ok so i put delta Y but it can also be delta X it just means displacement... i put delta Y because these kids are falling straight down in a rollercoaster like space mountain or something... ok lets do some replacing am i right?...

$\frac{1}{2}(9.8)(2.3^{2}) + 0(2.3)$

LISTEN! forget about the zero times 2.3 its just gonna be zero anyways.

so lets calculate... and we get 25.921 meters (or if you want to round to 2 sig figs then its 26 meters)

have a swag day

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Does the sun always shine directly overhead at the equator at noon

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3 years ago

Now the elevator is moving downward with a velocity of v = -2.8 m/s but accelerating upward with an acceleration of a = 5.5 m/s2

borishaifa [10]

Answer:

160.75 N

Explanation:

The downward velocity has no effect on the force situation, it is only changes in velocity (plus, of course, gravity, which is always there) that require a force. At constant velocity, the bottom spring s_3 is supporting its mass m_3 to balance gravity.

As the elevator slows, though, it also ends up slowing down the spring arrangement, too. However, because the stretching takes time, it means that some damped harmonic motion will be set up in the spring chain.

When the motion has finally damped out, the net force the bottom spring s3 exerts on m3 has two components--that of gravity and of the deceleration of the elevator:

F_3net = m3 * (g + a) = 10.5×(9.81+5.5)= 10.5×15.31= 160.75 N

5 0

3 years ago

An object is placed 5.00 cm beyond the focal point of a convex lens whose focal length is 10.0 cm. If the object height is 3.0 c

Aleks04 [339]

Answer:

The height of the image is, h' = 6.0 cm

The image is erect.

Explanation:

Given data,

The object distance, u = -5 cm

The focal length of convex lens, f = 10 cm