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kaheart [24]
3 years ago
14

This is a velocity versus time graph of a car starting from rest. If the area under the line is 10 meters: what is the correspon

ding time interval?
A. 2 seconds
B. 4 seconds
C. 5 seconds
D. 10 seconds
E. 15 seconds

Physics
1 answer:
shtirl [24]3 years ago
6 0

Answer: The correct answer is option (D).

Explanation:

The area under the line is 10 meters that is displacement which means that area enclosed by the right angled triangle is 10 unit squares.

So, the it can be written as:

\text{area of triangle}=\frac{1}{2}\times velocity\times time

10=\frac{1}{2}\times 2.0 m/s\times time

time =10 seconds

Hence the, the correct answer is option (D).

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U = 0, initial vertical velocity
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Ignore air resistance and take g = 32 ft/s².
It t = time to attain 60 mph, then
(88 ft/s) = (32 ft/s²)*(t s)
t = 88/32 = 2.75 s

Answer: 2.75 s
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Answer:

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Review. A light spring of force constant 3.85 N/m is compressed by 8.00 cm and held between a 0.250-kg block on the left and a 0
vivado [14]

The spring exerts on each block an outward force of magnitude

$$\left|\mathrm{F}_{\mathrm{s}}\right|=\mathrm{kx}=(3.85 \mathrm{~N} / \mathrm{m})(0.08 \mathrm{~m})=0.308 \mathrm{~N}$$

$$Take the $+\mathrm{x}$ direction to the right. For the light block on the left, the vertical forces are given by$$

$$\mathrm{F}_{\mathrm{g}}=\mathrm{mg}=(0.250 \mathrm{~kg})\left(9.80 \mathrm{~m} / \mathrm{s}^2\right)=2.45 \mathrm{~N}$$ \\and \ $\sum \mathrm{F}_{\mathrm{y}}=0$so $\mathrm{n}-2.45 \mathrm{~N}=0 \rightarrow \mathrm{n}=2.45 \mathrm{~N}$ \\Similarly, for the heavier block,$$

$$\mathrm{n}=\mathrm{F}_{\mathrm{g}}=(0.500 \mathrm{~kg})\left(9.80 \mathrm{~m} / \mathrm{s}^2\right)=4.90 \mathrm{~N}$$

$$\begin{aligned}&\sum F_x=m a_x:-0.308 \mathrm{~N}=(0.250 \mathrm{~kg}) \mathrm{a} \\&\mathrm{a}=-1.23 \mathrm{~m} / \mathrm{s}^2\end{aligned}$$\\\\$$ For the heavier block, \\$$+0.308 \mathrm{~N}=(0.500 \mathrm{~kg}) \mathrm{a}$$$$\mathrm{a}=0.616 \mathrm{~m} / \mathrm{s}^2$$

<h3>What is kinetic energy?</h3>

The kinetic energy  is the energy that it possesses due to its motion.

To accelerate an object, we need to apply force. To apply force, we have to be compelled to do work. When work is done on an object, energy is exchanged, and the object moves with a unused steady speed. We call the energy that's exchanged kinetic energy, and it depends on the mass and speed accomplished.

Kinetic energy is a scalar quantity, it is entirely described by magnitude

To learn more about kinetic energy , visit:

brainly.com/question/11592500

#SPJ4

7 0
2 years ago
A car rolls along a surface with a coefficient of friction of .795 I f the car has a mass of 905 kg, what force is needed to acc
Mumz [18]
102.5 km/hr = 28.5 m/s
a = (28.5 - 0) / 10
a = 2.85 m/s²

Resultant force = forward force - friction
ma = F - μmg
F = ma + μmg
F = 905(2.85 + 0.795 x 9.81)
F = 9637.3 N
F = 9600 N
4 0
3 years ago
A glass ball of radius 3.74 cm sits at the bottom of a container of milk that has a density of 1.04 g/cm3. The normal force on t
Gelneren [198K]

Answer:

The mass of the ball is 0.23 kg

Explanation:

Given that

radius ,r= 3.74 cm

Density of the milk ,ρ = 1.04 g/cm³ = 1.04  x 10⁻³ kg/cm³

Normal force ,N= 9.03 x 10⁻² N

The volume of the ball V

V=\dfrac{4}{3}\pi r^3

V=\dfrac{4}{3}\times \pi \times 3.74^3\ cm^3

V= 219.13 cm³

The bouncy force on the ball = Fb

Fb = ρ V g

Fb  + N = m g

m=Mass of the ball = Density x volume

m = γ V    , γ =Density of the Ball

ρ V g  + N =  γ V g               ( take g= 10 m/s²)

\gamma =\dfrac{N+\rho V g}{V g}

\gamma =\dfrac{9.03\times 10^{-2}+1.04\times 10^{-3}\times 219.13\times  10}{219.13\times 10}

γ = 0.00108 kg/cm³

m = γ V

m = 0.00108 x 219.13

m= 0.23 kg

The mass of the ball is 0.23 kg

5 0
3 years ago
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