<em>The gravitational force between two objects is inversely proportional to the square of the distance between the two objects.</em>
The gravitational force between two objects is proportional to the product of the masses of the two objects.
The gravitational force between two objects is proportional to the square of the distance between the two objects. <em> no</em>
The gravitational force between two objects is inversely proportional to the distance between the two objects. <em> no</em>
The gravitational force between two objects is proportional to the distance between the two objects. <em> no</em>
The gravitational force between two objects is inversely proportional to the product of the masses of the two objects. <em> no</em>
If the applied force is in the same direction as the object's displacement, the work done on the object is:
W = Fd
W = work, F = force, d = displacement
Given values:
F = 45N
d = 12m
Plug in and solve for W:
W = 45(12)
W = 540J
The answer is:
V = d/t d = 86 km t = 1.3 hrs
V = 86 km/ 1.3 hrs
V = 66.15 km/ hrs
I hope this helps!!
Answer:
2917.4 m/s
Explanation:
From the question given above, the following data were:
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
Radius (r) of the Moon = 1737 Km
Escape velocity (v) =?
Next, we shall determine the gravitational acceleration of the Moon. This can be obtained as follow:
Gravitational acceleration of the earth = 9.8 m/s²
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
= 0.25 × 9.8 = 2.45 m/s²
Next, we shall convert 1737 Km to metres (m). This can be obtained as follow:
1 Km = 1000 m
Therefore,
1737 Km = 1737 Km × 1000 m / 1 Km
1737 Km = 1737000 m
Thus, 1737 Km is equivalent to 1737000 m
Finally, we shall determine the escape velocity of the rocket as shown below:
Gravitational acceleration of the Moon (g) = 2.45 m/s²
Radius (r) of the moon = 1737000 m
Escape velocity (v) =?
v = √2gr
v = √(2 × 2.45 × 1737000)
v = √8511300
v = 2917.4 m/s
Thus, the escape velocity is 2917.4 m/s
Answer:
Explanation:
30 rev/min (2π rad/rev) / (60 s/min) = π rad/s
α = Δω/t = (0 - π)/3 = π/3 rad/s²
θ = ½αt² = ½(π/3)3² = 1.5π radians
θ = 1.5π rad/2π rad/rev = 0.75 rev