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vladimir2022 [97]
3 years ago
6

What makes a grenade explode?

Physics
1 answer:
motikmotik3 years ago
6 0
The striker throws the safety lever away from the grenade<span> body as it rotates to detonate the primer. The primer </span>explodes<span> and ignites the fuse  The fuse burns down to the detonator, which </span>explodes<span> the main charge</span>
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Simone is walking her dog on a leash. The dog is pulling with a force of 32 N to the right and Simone is pulling backward with a
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Answer:1.16

2.unbalanced

Explanation:

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As we increase the frequency of this light, but do not vary anything else (there may be more than one correct answer),
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The answer is c hope this helps
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Why is the work output of a machine never equal to the work input? A. Some work input is used to overcome friction. B. Input dis
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Driving on asphalt roads entails very little rolling resistance, so most of the energy of the engine goes to overcoming air resi
nirvana33 [79]

Answer:

a) F = 882.63\,N, b) \dot W= 4413.15\,W, c) \eta = 15.216\,\%.

Explanation:

a) Let assume that car travel on a horizontal surface. The equations of equilibrium of the car are:

\Sigma F_{x} = F - \mu_{r}\cdot N = 0

\Sigma F_{y} = N - m\cdot g = 0

After some algebraic handling, the following expression for the propulsion force is constructed:

F = \mu_{r}\cdot m \cdot g

F = (0.06)\cdot (1500\,kg)\cdot (9.807\,\frac{m}{s^{2}} )

F = 882.63\,N

b) The power require to move the car at a speed of 5 meters per second is:

\dot W = F\cdot v

\dot W = (882.63\,N)\cdot (5\,\frac{m}{s} )

\dot W= 4413.15\,W

c) The efficiency of the car is:

\eta = \frac{(882.63\,N)\cdot (15\,mi)\cdot (\frac{1609\,m}{1\,mi} )}{(1.4\times 10^{8}\,J)} \times 100\,\%

\eta = 15.216\,\%

3 0
3 years ago
sing a rope that will snap if the tension in it exceeds 361 N, you need to lower a bundle of old roofing material weighing 455 N
yaroslaw [1]

Answer:

a)-2m/s^2

b)27.2m/s

Explanation:

Hello! The first step to solve this problem is to find the mass of the block remembering that the definition of weight force is mass by gravity (g=9.8m / s ^ 2)

W=455N=weight

W=mg

W=455N=weight

m=\frac{W}{g} =\frac{455}{9.81}=46.38kg

The second step is to draw the free body diagram of the body (see attached image) and use Newton's second law that states that the sum of the forces is equal to mass by acceleration

a=\frac{T-W}{m} =\frac{361-455}{46.38kg} =-2m/s^2

for point b we use the equations of motion with constant acceleration to find the velocity

Vf=\sqrt{X(2)(a)+Vo^2}

Where

Vf = final speed

Vo = Initial speed =0

A = acceleration =2m/s

X = displacement =6.8m

Solving

Vf=\sqrt{(6.8)(2)(2)+0^2}=27.2m/s

4 0
3 years ago
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