[19] x2 [38]x2[76]x2[152]x2[304] this is the answer
If u want to know how I get it than divide the number in the box by 2 than u will get the first two missing number than last u divide 152 by 2 to get the last missing number
Six and one sixth or 6 1/6
Answer:
x=7/6
Step-by-step explanation:
subtract the 4x from both sides of the equation
(2x+6)-4x=4x-3-4x
find common denominator
(2x+6)/5+(5(-4)x)/5=4x-3-4x
then combine fractions
(2x+6+5(-4)x)/5=4x-3-4x
then multiply the 5&4
(2x+6-20x)/5= 4x3-4x
combine terms
(-18x+6)/5= -3
then multiply everything by 5
-18x+6= -15
subtract the 6 from both sides
-18x= -21
divide -21 by -18
(-21)/(-18)=x
find greatest common multiple (3) and solve
x = 7/6
N-10 because you want to take 10 away from n
