B^-2 / b^-3 = b^(-2-(-3) = b^1 = b
answer is d
Answer:
Not rlly sure, might be x=4/5y??? i dont know
You got the right answers!
Horizontal and vertical
Congrats
Answer:
x = 11º
Step-by-step explanation:
1. Notice Parallel Lines
2. Understand Angle Relationships When Parallel Lines Are Present (e.g., alternate interior/exterior)
3. ∠CAB ≅ ∠DCA ∴ m∠CAB = 33º
4. Use exterior angle theorem: the sum of non-adjacent angles of the same triangle which the exterior angle is drawn is equal to the measure of that angle.
5. Therefore write and solve the equation 2x + 33º (sum of non-adjacent interior angles) = 5x (exterior angle).
- 2x + 33 = 5x (C.L.T or <u>C</u>ombine <u>L</u>ike <u>T</u>erms)
- 3x = 33 (inverse operations; divide by 3)
- x = 11º (remember to apply units)
