Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
-1.43*0.11= -0.1573
That should be it
Answer:
c = -20
Step-by-step explanation:
-21=1/2c-11
-21+11=1/2c
-10=1/2c
-10*2=c
-20=c
AB & CD
they have the same degree & are equally apart.
Answer:
the answer is 612 -4n4+6n-5772