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ahrayia [7]
2 years ago
14

What is the balanced form of the chemical equation shown below? C12H22O11(I) + O2(g) -> H2O(I)

Chemistry
1 answer:
Mariulka [41]2 years ago
7 0

C_{12}H_{22}O_{11} + 12O_2  → 12CO_2 + 11H_2O is the balanced form of the chemical equation.

<h3>What is the balanced equation?</h3>

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge are the same for both the reactants and the products.

12 hydrogen, 35 oxygen, and 22 hydrogens are present on both sides of the reaction.

C_{12}H_{22}O_{11} + 12O_2  → 12CO_2 + 11H_2O

Learn more about the balanced equation here:

brainly.com/question/15052184

#SPJ1

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Which of the following are supported by many observations
Readme [11.4K]

Which of the following are supported by many observations

A- hypothesis

B- laws

C- theories



Laws and Theories

5 0
3 years ago
HELPPP!!! What is the volume of a 1.31 moles sample of gas if the pressure is 904 mmHg and the temperature is 37. degrees Celsiu
Tju [1.3M]

Answer:

27.99 dm³

Explanation:

Applying

PV = nRT................ Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

From the question, we were aksed to find V.

Therefore we make V the subject of the equation

V = nRT/P................ Equation 2

Given: n = 1.31 moles, T = 37°C = 310K, P = 904 mmHg = (904×0.001316) = 1.1897 atm

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

V = (1.31×310×0.082)/(1.1897)

V = 27.99 dm³

4 0
3 years ago
An aqueous salt solution is 15.0% mass sodium chloride. How many grams of salt are in 250.0 grams of this solution? Use correct
Shtirlitz [24]

Answer:

37.5 g NaCl

Explanation:

Step 1: Given data

  • Concentration of NaCl: 15.0% m/m
  • Mass of the solution: 250.0 g

Step 2: Calculate how many grams of NaCl are in 250.0 g of solution

The concentration of NaCl is 15.0% by mass, that is, there are 15.0 g of NaCl every 100 g of solution.

250.0 g Solution × 15.0 g NaCl/100 g Solution = 37.5 g NaCl

5 0
3 years ago
____________ is the process of separating a mixture of a liquid and a solid by straining it through a porous material.
PIT_PIT [208]
It is C) filtration.
3 0
4 years ago
Predict the ground-state electron configuration of the following ions. Write your answers in abbreviated form, that is, beginnin
abruzzese [7]

These are three questions and three complete answers

Answer:

a) Cr²⁺: [Ar] 4s² 3d²

b) Cu²⁺: [Ar] 4s² 3d⁷

c) Co³⁺: [Ar] 4s² 3d⁴

Explanation:

<u>a) Cr²⁺</u>

  • Z = 24
  • Number of protons: 24
  • Number of elecrons of the neutral atom: 24
  • Charge of the ions: + 2
  • Number of electrons of the ion: 24 - charge = 24 - 2 = 22.
  • Electron configuration:

       Fill the orbitals in increasing order of energy. Using Aufbau's rules the order is: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ .....

       Hence, for 22 electrons you get:

       1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d²

  • Abbreviated notation: since the last complete level is the number 3s² 3p⁶, you use the noble gas of the period 3, which is Ar, and the configuration is:

       

        [Ar] 4s² 3d²

<u>b) Cu²⁺</u>

  • Z = 29
  • Number of protons: 29
  • Number of elecrons of the neutral atom: 29
  • Charge of the ion: + 2
  • Number of electrons of the ion: 29 - charge = 29 - 2 = 27.
  • Electron configuration:

       Fill the orbitals in increasing order of energy. Using Aufbau's rules the order is: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ .....

       Hence, for 27 electrons you get:

       1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁷

  • Abbreviated notation: since the last complete level is the number 3s² 3p⁶, you use the noble gas of the period 3, which is Ar, and the configuration is:

       

        [Ar] 4s² 3d⁷

<u>c) Co³⁺</u>

  • Z = 27
  • Number of protons: 27
  • Number of elecrons of the neutral atom: 27
  • Charge of the ion: + 3
  • Number of electrons of the ion: 27 - charge = 27 - 3 = 24.
  • Electron configuration:

       Fill the orbitals in increasing order of energy. Using Aufbau's rules the order is: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ .....

       Hence, for 24 electrons you get:

       1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁴

  • Abbreviated notation: since the last complete level is the number 3s² 3p⁶, you use the noble gas of the period 3, which is Ar, and the configuration is:

       

        [Ar] 4s² 3d⁴

6 0
3 years ago
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