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3 years ago

What is the balanced form of the chemical equation shown below? C12H22O11(I) + O2(g) -> H2O(I)

Chemistry

1 answer:

Mariulka [41]3 years ago

7 0

$C_{12}H_{22}O_{11} + 12O_2$ → $12CO_2 + 11H_2O$ is the balanced form of the chemical equation.

<h3>What is the balanced equation?</h3>

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge are the same for both the reactants and the products.

12 hydrogen, 35 oxygen, and 22 hydrogens are present on both sides of the reaction.

$C_{12}H_{22}O_{11} + 12O_2$ → $12CO_2 + 11H_2O$

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VLD [36.1K]

Answer:

imma have to say kinetic energy is transferred to the wheels 2 or b

Explanation:

5 0

3 years ago

You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.140 M sodium benzoate. H

malfutka [58]

Answer:

The volume of benzoic acid = 68.93 mL

The volume of benzoate = 31.07 mL

Explanation:

Since benzoic acid and sodium benzoate is a buffer of a weak acid/weak base, we can use the formula of Henderson-Hasselbalch equation.

pH = pKa + log [A-]/[HA]

with [A-] = Benzoate

with [HA] = Benzoic acid

This gives us:

4 = 4.2 + log [A-]/[HA]

[A-]/[HA] = 10^(4-4.2)

[A-]/[HA] = 10^-0.2

[A-]/[HA] = 0.631

This ratio is not the ratio of the initial concentration, but the ratio in the buffer ( after this buffer is finalized).

The solution has only one total volume, we only need to determine the initial volumes necessary to accomplish this 0.631 ratio.

0.631 = (0.140M *V(A-)) / (0.100M*V(HA)

Since the total voume = 100mL

V(A-) ≈ 100 mL - V(HA)

This gives us:

0.631 = (0.140M * (100 - VHA))/ (0.100M * VHA)

IF we say x = VHA we'll have the equation:

0.631 = 0.140 *(100- x)/(0.100 *x)

0.0631x +0.14x = 14

x = 68.93

V(HA) = 68.93 mL

This means V(A-) is 100 - 68.93 = 31.07 mL

We can control this by the following equation:

0.140 M benzoate * 31.07 mL / 100 mL = 0.0435M A-

0.100 M Benzoic acid * 68.93 mL /100 mL = 0.06893 M HA

[A-]/[HA] = 0.0435/0.06893 = 0.631

This means the volume of benzoic acid = 68.93 mL

The volume of benzoate = 31.07 mL

4 0

3 years ago

Determine the mass in grams of carbon that contains as many molecukes as 21g of krypton.

qaws [65]

The mass in grams of carbon that contains as many molecules as 21g of krypton is 3 grams.

<h3>What is molecular mass?</h3>

An element's molecular mass is defined as the total of the masses of a elements that make up the molecule. A atomic mass of an element is multiplied by the number of atoms present in the molecule, and then the masses of all of the elements in the molecule are added.

The molecular mass of carbon is 12 g/mol.

The molecular mass of krypton is 84 g/mol.

Now according to the question;

To begin, we must determine the number of moles in 21 g of Krypton by dividing the above mass by the molar mass of Krypton.

n = m/μ

m is the mass of carbon = 21 g.

μ is the molecular mass of the krypton = 84 g/mol.

Substitute the values;

n = 21/84

n = 0.25 mol.

Now, calculate the mass of (0.25 mol) of carbon, which we can do by simply multiplying the number of moles by the molar mass of carbon;

m = n×μ

n = number of moles = 0.25 mol

μ = molecular mass of carbon = 12 g/mol

m = 0.25×12

m = 3 g.

Therefore, the mass of the carbon is evaluated as 3 g.

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8 0

2 years ago

An exothermic reaction always _____.

masha68 [24]

Releases heat
(Exothermic)

4 0

4 years ago

42.Which equation shows that the total mas during a chemical reaction stays the same

Brrunno [24]

the answer is (C)3 for the above question

8 0

4 years ago