Explanation:
Reaction:
Cu + 2AgC₂H₃O₂ → Cu(C₂H₃O₂)₂ + 2Ag
The problem is to split the reaction into oxidation and reduction halves:
The oxidation half is the sub-reaction that undergoes oxidation
The reduction half is the one that undergoes reduction:
The ionic equation:
Cu + 2Ag⁺ + 2C₂H₃O₂⁻ → Cu²⁺ + 2C₂H₃O₂⁻ + 2Ag
Oxidation half:
Cu → Cu²⁺ + 2e⁻
Reduction half:
2Ag⁺ + 2e⁻ → 2Ag
C₂H₃O₂⁻ is neither oxidized nor reduced in the reaction.
learn more:
Oxidation state brainly.com/question/10017129
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Answer is: same orbital, but have different spin directions.
The principal quantum number (n) is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.
For principal quantum number n=2:
1) azimuthal quantum number (l) can be l = 0...n-1:
l = 0, 1.
The azimuthal quantum number determines its orbital angular momentum and describes the shape of the orbital.
2) magnetic quantum number (ml) can be ml = -l...+l.
ml = -1, 0,+1.
Magnetic quantum number specify orientation of electrons in magnetic field and number of electron states (orbitals) in subshells.
3) the spin quantum number (ms), is the spin of the electron.
ms = +1/2, -1/2.
Answer:
+4
Explanation:
Oxidation number of neutral compound is 0
Oxidation number of hydrogen in methane is -1
C + (-1×4) = 0
C - 4 = 0
C = 4
Answer:
aa
Explanation:
There is a lowercase a on both sides.
Answer:
I also have this question but see the 69 page of ur question book