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____ [38]
3 years ago
14

What is true of an Arrhenius acid?

Chemistry
1 answer:
expeople1 [14]3 years ago
5 0
<span>B, An Arrhenius acid donates H+ ions.</span>
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When a boron atom loses its valence electrons, what is the formula for the resulting ion?
kirill [66]

Answer:

option b. B3+

Explanation:

Boron takes the 5th position on the periodic table, therefore it has 5 electrons....2 on the inside and 3 on the outside. when it lost it 3 external electrons, it become positively charged with the amount of electron it loses.

8 0
3 years ago
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A certain compound is made up of one phosphorus (P) atom, three chlorine (Cl) atoms, and one oxygen (O) atom. What is the chemic
yulyashka [42]

Answer: PCl₃O

Explanation:

1) The chemical formula tells the composition of a compound in terms of the ratio of number of atoms of each element that consitutes such compound.

2) You use the chemical symbol for each kind of atom (element) and subscripts to the right of each symbol to tell the number of atoms of each element.

3) For example, O₂ means two atoms of oxygen. Al₂O₃ means two atoms of aluminum and 3 atoms of oxygen.

4) Therefore, PCl₃O means a ratio 1 : 3 : 1 for phosphorus, chlorine, and oxygen.

Hence, PCl₃O is the chemical formula of your compound.

3 0
3 years ago
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224/88Ra+4/2He+? find the missing isotope
andre [41]
Do u have a picture if so post it please
8 0
3 years ago
What product of an acid base reaction is an ionic compound apex?
charle [14.2K]
When acids react with bases they produce salt and water such as:
HCl + NaOH → NaCl + H₂O
According to strength of acid and base, we have 4 types of salts:
salt of strong acid and strong base like: NaCl
salt of weak acid and strong base like: CH₃COONa
salt of strong acid and weak base like: NH₄Cl
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8 0
3 years ago
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What is the ph of a solution of 0.550 m k2hpo4, potassium hydrogen phosphate?
Solnce55 [7]
We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+  + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
z= 4.81x10^-7
∴[H+] = 4.81x10^-7
when PH equation is:

PH= -㏒[H+]
     = -㏒(4.81x10^-7) = 6.32

3 0
3 years ago
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