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Mumz [18]
3 years ago
9

Suppose that you are asked to pick a card from a deck of 52 cards. Once you have selected a card, you place it face down on the

table. You are then asked to selected another card from the deck. Is the event of you picking the first card going to affect the probability of the second card selected, why or why not? Are these events independent or dependent?
Mathematics
1 answer:
serg [7]3 years ago
8 0

Answer:

Step-by-step explanation:

The second card is influenced by the first only in that you have not replaced the first card. That makes a difference.

1/52 is the probability for the first card.

1/51 is the probability for the second card.

They are independent events. Drawing the 7 of diamonds does not make the chances of drawing the Ace of Spades other than the 7 came first and the probability of getting the Ace is slightly larger.

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Step-by-step explanation:

This is an example of scalar multiplication in matrices.

Just multiply the number outside with each of the number inside for this type of matrix.

That's all.

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4 years ago
I need help with algebra, Can someone help me pls?<br> Y=2x-4<br> X+2y=10
denis23 [38]
Y=2x-4
X=2
X+2y=10
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X+0=10 therefore, x=10
4 0
3 years ago
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Answer:

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3 years ago
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lozanna [386]

4k-2z=8

Move -2z to the other side. Sign changes from -2z to + 2z

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Recall that sine is the ratio of opposite over hypotenuse, so we say

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Then from here we use a bit of algebra to compute the left hand side of the given equation. The goal is to see if we can simplify it to 1.

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So this shows that the left hand side is identically the same as the right hand side (both sides are 1), and it doesn't matter what you replace theta with. Theta can be any real number and the equation will always be true.

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