Which of the following molecules has a double bond? A. butane B. 2-butyne C. cyclopentane D. 1-methylcyclohexene

Diamond has a density of 3.52 g/ml. what is the volume in cubic centimeters of a diamond with a mass of 15.1 g? 4.3 cm3 4.29 cm3

Kamila [148]

Density of 3.52g/ml means for each milliliter of space there are 3.52 grams of diamond.

To set the stage:
$\frac{3.52}{1} = \frac{15.1}{x}$
Set the denominators equal:
$\frac{3.52x}{x} = \frac{15.1}{x}$
Remove the denominators:
$3.52x = 15.1$
Isolate x by dividing both sides by 3.52:
$x = 4.289772 {cm}^{3}$

6 0

3 years ago

Read 2 more answers

What is the density of helium gas at 17 degrees celcius and 773 torr?

valina [46]

Answer:

0.172g/L

Explanation:

Step 1:

Data obtained from the question:

Temperature (T) = 17°C

Pressure (P) = 773 torr

Step 2:

Conversion to appropriate unit:

For pressure :

760 torr = 1 atm

Therefore, 773 torr = 773/760 = 1.02 atm

For temperature:

Temperature (Kelvin) = temperature (celsius) + 273

temperature (celsius) = 17°C

Temperature (Kelvin) = 17°C + 273 = 290K.

Step 3:

Obtaining an expression for the density.

From the ideal gas equation PV = nRT, we can obtain an equation for the density as follow:

PV = nRT. (1)

But: number of mole(n) = mass (m)/Molar Mass(M) i.e

n = m/M

Substitute the value of n into equation 1

PV = nRT

PV = mRT/M

Divide both side by m

PV /m = RT/M

Divide both side by P

V/m = RT/MP

Invert the above equation

m/V = MP/RT (2)

Recall:

density (d) = mass(m) / volume(V) i.e

d = m/V

Replace m/V in equation 2 with d

m/V = MP/RT

d = MP/RT.

Step 4:

Determination of the density.

Temperature (T) = 290K

Pressure (P) = 1.02 atm

Molar Mass of helium (M) = 4g/mol

Gas constant (R) = 0.082atm.L/Kmol

Density (d) =?

d = MP/RT

d = 4 x 1.02 / 0.082 x 290

d = 0.172g/L

Therefore, the density of the helium gas is 0.172g/L

7 0

2 years ago

Assuming all volume measurements are made at the same temperature and pressure, how many liters of water vapor can be produced w

maria [59]

For the reaction 2 K + F2 --> 2 KF,
consider K atomic wt. = 39
23.5 g of K = 0.603 moles, hence following the molar ratio of the balanced equation, 0.603 moles of potassium will use 0.3015 moles of F2. (number of moles, n = 0.3015)

Now, following the ideal gas equation, PV = nRT
P = 0.98 atm
V = unknown
n = 0.3015 moles
R = 82.057 cm^3 atm K^-1mole^-1 (unit of R chosen to match the units of other parameters; see the reference below)
T = 298 K
Solving for V,
V = (nRT)/P = (0.3015 mol * 82.057 cm^3 atm K^-1 mol^-1 * 298 K)/(0.98 atm)
solve it to get 7517.6 cm^3 as the volume of F2 = 7.5176 liters of F2 gas is needed.

2. Use the formula: volume1 * concentration 1 = volume 2 * concentration 2
where, volume 1 and concentration 1 are for solution 1 and volume 2 and solution 2 for solution 2.

Solution 1 = 12.3 M NaOH solution
Solution 2 = 1.2 M NaOH solution

<span> Solving for volume 1, volume 1 = (12.4 L * 1.2 M)/12.3 M = 0.1366 L </span>

5 0

3 years ago

In a 5.609g of H20, how many molecules H20<br> arc<br> present?

nignag [31]

Answer:

1.88 x 10²³molecules of H₂O

Explanation:

Given parameters:

Mass of H₂O = 5.609g

Unknown:

Number of molecules of H₂O = ?

Solution:

To solve this problem, we need to find the number of moles of given compound first.

Number of moles = $\frac{mass}{molar mass}$

Molar mass of H₂O = 2(1) + 16 = 18g/mol

Number of moles = $\frac{5.609}{18}$ = 0.31mole

From mole concept;

1 mole of a substance contains 6.02 x 10²³molecules

0.31 mole of H₂O will therefore contain 0.31 x 6.02 x 10²³molecules

= 1.88 x 10²³molecules of H₂O

8 0

3 years ago

Write a balanced chemical equation for the reaction that occurs when barium carbonate decomposes into barium oxide and carbon di

n200080 [17]

BaCO3=BaO+CO2
IS THE EQUATION REPLACE = WITH AN ARROW.

4 0

3 years ago