Answer is: pH of aniline is 9.13.<span>
Chemical reaction: C</span>₆H₅NH₂(aq)+
H₂O(l) ⇌ C₆H₅NH₃⁺(aq) + OH⁻(aq).
pKb(C₆H₅NH₂) = 9.40.
Kb(C₆H₅NH₂) = 10∧(-9.4) = 4·10⁻¹⁰.
c₀(C₆H₅NH₂) = 0.45 M.
c(C₆H₅NH₃⁺) = c(OH⁻) = x.
c(C₆H₅NH₂) = 0.45 M - x.
Kb = c(C₆H₅NH₃⁺) · c(OH⁻) / c(C₆H₅NH₂).
4·10⁻¹⁰ = x² / (0.45 M - x).
Solve quadratic equation: x = c(OH⁻) = 0.0000134 M.
pOH = -log(0.0000134 M.) = 4.87.
pH = 14 - 4.87 = 9.13.
Answer:
Metal
Explanation:
In chemistry, an alkali is a basic, ionic salt of an alkali metal or alkaline earth metal chemical element. An alkali also can be defined as a base that dissolves in water. A solution of a soluble base has a pH greater than 7.0.
Answer: Volume would be 196.15 mL if the temperature were changed to 
and the pressure to 1.25 atmospheres.
Explanation:
Given: 
, 
= 256 mL,
= 720 torr (1 torr = 0.00131579 atm) = 0.947368 atm
, 
Formula used to calculate volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the volume would be 196.15 mL if the temperature were changed to and the pressure to 1.25 atmospheres.
Answer:
0.74mol
Explanation:
4.5×10^23/6.02×10^23=0.74mol
