Answer is: <span>to decrease activation energy.
Manganese(IV) oxide is catalyst in this reaction.
</span>Catalysis <span>is the increase in the </span>rate<span> of a </span>chemical reaction<span> due to the participation of an additional substance called a </span>catalyst. R<span>eactions occur faster with a catalyst because they require less </span>activation energy<span>.</span>
Assuming that the gas is ideal, we can use the ideal gas equation PV=nRT to calculate for the number of moles. Then, multiply the molar mass of the gas to obtain the mass. We do as follows:
PV = nRT
n = PV / RT
n = 1.1 atm (3.7x10^9 L) / 0.08205 L-atm/mol-K (280.15) = 177061931.3 mol H2
Mass = (177061931.3 mol H2) 18.02 g/mol ( 1 kg / 1000g) ( 2.2 lb / 1 kg ) = 7019443.21 lb H2
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