The answer is competition. It's competition because they are protecting their territory, so their way of protecting or fighting for their territory is to urinate on their territory. By a way of showing that they don't want nobody in their territory.
Answer: 22368.4 Liters
Explanation:
Initial Volume of gas V1 = 20000 liters
Initial pressure of gas P1 = 850 torr
Final volume V2 = ?
Final (standard) pressure P2 = 760 torr
Apply the formula for Boyle's law:
P1V1 = P2V2
850torr x 20000L = 760torr x V2
V2 = (850torr x 20000L)/ 760torr
V2 = (17000000)/760torr
V2 = 22368.4L
Thus, the volume of the gas at standard pressure is 22368.4 Liters
Answer: Ethyl Ethanoate can be used as a developing solvent. It’s safer.
Explanation:Di ethyl ether should be carefully used because it’s highly flammable and intoxicating when inhaled and can cause explosions because of its high reactivity to air and light.
Mg reaction with O₂ gas will produce MgO so the equation will be
2Mg+O₂⇒2MgO. (You have to find the equation in order two figure out the number of moles of O₂ that will react with 1 mole of MgO).
The first step is to find the number of moles of Mg in 4.03g of Mg. You can do this by dividing 4.03g Mg by its molar mass (which is 24.3g/mol) to get 0.1658mol Mg. Then you have to find the number of moles of O₂ that will react with 0.1658mol Mg. To do this you need to use the fact that 1mol O₂ will react with 2mol Mg (this reatio is from the chemical equation) so you have to multiply 0.1658mol Mg by (1mol O₂)/(2mol Mg) to get 0.0829mol O₂. From here you would usually use PV=nRT and solve for V However, the question tells us that we are at STP, that means you can use the fact that 22.4L of gas is 1 mol of gas at STP. Using that information we can find the volume of O₂ gas by mulitlying 0.0829mol O₂ by 22.4L/mol to get 1.857L which equals 1857mL.
therefore, 1857mL of O₂ gas will react with 4.03g of Mg.
I hope this helps. Let me know in the comments if anything is unclear.
