Question

Which equation shows a valid step in solving /2x-6+2x+6=0?

Answer 1

An equation which shows a valid step that can be used to solve the given mathematical equation is $(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3$

What is an equation?

An equation simply refers to a mathematical expression that can be used to show the relationship existing between two (2) or more numerical quantities.

In this exercise, you're required to show a valid step which can be used to solve the given mathematical equation. Since both equations are having a cube root, the first step is to take the cube of both sides.

Take the cube of both sides, we have:

$\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0\\\\(\sqrt[3]{2x - 6})^3 + (\sqrt[3]{2x + 6})^3 = 0^3\\\\(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3$

Read more on equations here: brainly.com/question/13170908

#SPJ1