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2 years ago

Question Number 4 on Straight Lines

Mathematics

1 answer:

Ivanshal [37]2 years ago

8 0

Answer:

a) $y = \frac{3}{2}x - 6$

b) x intercept = 4

Step-by-step explanation:

Given equation of line 1

$y - 4 = \frac{3}{2} (x-1)\\\\y = \frac{3}{2}x -\frac{3}{2} + 4\\\\y = \frac{3}{2} x + \frac{5}{4}$

The two lines are parallel to each other, therefore they have same slope.

Given

$Slope \ of \ line, \ m_1 = \frac{3}{2}$

Therefore

$slope \ of \ line, m_2 = \frac{3}{2}$

Equation of line 2:

$(y-3) =\frac{3}{2}(x -6)\\\\y = \frac{3}{2}x -9 + 3\\\\y = \frac{3}{2} x- 6$

x - intercept of line 2: Value of x at y = 0

$0 = \frac{3}{2}x - 6\\\\\frac{3}{2}x = 6\\\\3x = 12\\\\x = 4$

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Help please!!!!!!!!!

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ANSWER

EXPLANATION

For a matrix A of order n×n, the cofactor $C_{ij}$ of element $a_{ij}$ is defined to be

$C_{ij} = (-1)^{i+j} M_{ij}$

$M_{ij}$ is the minor of element $a_{ij}$ equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.

Here, we have

$C_{11} = (-1)^{1+1} M_{11} = M_{11}$

M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.

$\begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \end{aligned}$