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sladkih [1.3K]
3 years ago
11

How is the thermal energy of a radiator transferred to the surrounding air

Physics
1 answer:
Gwar [14]3 years ago
3 0

It is caused by conduction! :D


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The figure shows a 1 cm cube that has a mass of 1 gram. Calculate the density of the cube in kg/m³.
dolphi86 [110]
Density = 1 g/cm^3 = 1000 Kg/m^3
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3 years ago
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The answer to the problem b.
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What is the new volume of the gas if the pressure on 350 L of oxygen
Iteru [2.4K]

Answer:

420 L

Explanation:

Applying Boyle's Law,

PV = P'V'.................... Equation 1

Where P = Initial pressure, P' = Final pressure, V = Initial volume, V' = Final volume.

make V' the subject of the equation

V' = PV/P'.................... Equation 2

From the question,

Given: P = 720 mmHg, V = 350 L, P' = 600 mmHg

Substitute these values into equation 2

V' = (720×350)/600

V' = 252000/600

V' = 420 L

7 0
3 years ago
Two blocks of masses 20 kg and 8.0 kg are connected togetherby
OleMash [197]

Answer:

14 N

Explanation:

The tension in the second string is puling both the masses of 20 kg and 8 kg with acceleration of 0.5 m s⁻²

So tension in the second string = total mass x acceleration

= 28 x .5 = 14 N . Ans..

4 0
3 years ago
A 5.0-kg object is moving with speed 2.0 m/s. A 1.25-kg object is moving with speed 4.0 m/s Both objects encounter the same cons
Mademuasel [1]

Acceleration is constant, so we can use the following kinematic equation and Newton's second law.

{v_f}^2 - {v_i}^2 = 2a\Delta x \implies -{v_i}^2 = -2\dfrac{F}{m}\Delta x \implies {v_i}^2 = 2\dfrac{F}{m} \Delta x

where v_i and v_f are initial/final velocities, a is acceleration, \Delta x is displacment, F is force, and m is mass. Since the objects are coming to rest, the acceleration opposes the direction of motion and is negative.

Solve for \Delta x.

\Delta x = -\dfrac{m {v_i}^2}{2F}

Compute the displacements of both objects.

\Delta x_{5.0\text{-kg}} = -\dfrac{(5.0\,\mathrm{kg}) \left(2.0\frac{\rm m}{\rm s}\right)^2}{2F} = -\dfrac{10}F \dfrac{\rm m}{\rm N}

\Delta x_{1.25\text{-kg}} = -\dfrac{(1.25\,\mathrm{kg}) \left(4.0\frac{\rm m}{\rm s}\right)^2}{2F} = -\dfrac{10}F \dfrac{\rm m}{\rm N}

Then both objects are displaced by the same amount.

4 0
1 year ago
Read 2 more answers
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