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3 years ago

15

When the body said to be in equilibrium

2 answers:

Schach [20]3 years ago

7 0

Answer:

Oh! I just learned abt this

Explanation:

the body is said to be in equilibrium if it is resting or moving with uniform velocity.

zheka24 [161]3 years ago

5 0

Answer: The body is said to be in balance if it is at rest or moving at a uniform speed. In other words, if the body's linear and angular acceleration is zero, the body is said to be in balance. 1

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What happens inside when an air-filled, sealed can, is heated?.

g100num [7]

Answer:

It would explode

Explanation:

you're welcome

5 0

2 years ago

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Toon Train is traveling at the speed of 10 m/s at the top of a hill. Five seconds later it reaches the bottom of the hill and is

Naddika [18.5K]

Answer:

the rate of acceleration of the train is 4 m/s²

Explanation:

Given;

initial velocity of the train, u = 10 m/s

change in time of motion, dt = 5 s

final velocity of the train, v = 30 m/s

The rate of acceleration of the train is calculated as;

$a = \frac{dv}{dt} = \frac{v-u}{dt} = \frac{30-10}{5} = \frac{20}{5} = 4 \ m/s^2$

Therefore, the rate of acceleration of the train is 4 m/s²

5 0

3 years ago

Lincoln weighs 400 newtons. What’s his mass rounded to the nearest kilogram? Assume that acceleration due to gravity is 9.8 N/kg

Yanka [14]

Weight equals mass times gravitational acceleration=400N, so mass=400/9.8=41kg approx.

6 0

4 years ago

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The vertical force f acts downward at A on the two membered frames. Determine the magnitude of the two components of F directed

galben [10]

Answer:

The magnitude will be "353.5 N". A further solution is given below.

Explanation:

The given values is:

F = 500 N

According to the question,

In ΔABC,

⇒ $\angle BCA = (90-30)$

⇒ $=60^{\circ}$

then,

⇒ $\angle BAC=(180-45-60)$

⇒ $=75^{\circ}$

Now,

The corresponding angle will be:

⇒ $\angle FAC=60^{\circ}$

⇒ $\angle FAB=70+60$

⇒ $=135^{\circ}$

Aspect of F across the AC arm will be:

= $F\times cos(60)$

On putting the values of F, we get

= $500\times (.5)$

= $200 \ Newton$

Component F along the AC (in magnitude) will be:

= $F\times cos(135)$

= $500\times (-.707)$

= $-353.5 \ N \$

4 0

3 years ago

While driving north at 25 m/s during a rainstorm you notice that the rain makes an angle of 38° with the vertical. While driving

Natali [406]

Answer: $21.33^{\circ}$

Explanation:

Given

velocity of driver $v_1$ =25 m/s w.r.t ground towards north

driver observes that rain is making an angle of $38^{\circ}$ with vertical

While returning $v_2$ =25 m/s w.r.t. ground towards south

suppose $u_1$ =velocity of rain drop relative car while car is going towards north

$u_2$ =velocity of rain drop relative car while car is going towards south

z=vector sum of $u_1 & v_1$

Now from graph

$\tan 38=\frac{v_1+v_2}{u_2}$

$u_2=\frac{25+25}{\tan 38}=64 m/s$

$z=\vec{u_2}+\vec{v_2}$

therefore magnitude of z is given by

$|z|=\sqrt{u_2^2+v_2^2}$

$|z|=\sqrt{64^2+25^2}$

$|z|=68.70 m/s$

$\tan A=\frac{v_2}{u_2}$

$\tan A=\frac{25}{64}=0.3906$

$A=21.33^{\circ}$

Thus rain drops make an angle of $21.33^{\circ}$ w.r.t to ground

6 0

3 years ago