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Charra [1.4K]
2 years ago
11

How many grams of copper

Chemistry
1 answer:
iren [92.7K]2 years ago
7 0
  • <u>The</u><u> </u><u>mas</u><u> </u><u>of copper</u><u> </u><u>is</u><u> </u><u>217</u><u>.</u><u>3</u><u> </u><u>grams</u><u>.</u>
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What kind of radioactive element is useful for dating an object?
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The kind of radioactive element is useful for dating an object is one with a half-life close to the age of the object.

<h3>What are radioactive elements?</h3>

Radioactive elements are elements that involved in radioactivity and this comprises of atoms or particles in their nuclei whose atomic nuclei are not stable and they emit radiations to maintain stability.

Therefore, The kind of radioactive element is useful for dating an object is one with a half-life close to the age of the object.

Learn more about radioactive elements below.

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2 years ago
What type of wave moves the particles parallel to the motion of the wave
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3 years ago
The current human population is reaching nearly eight billion people and will continue to grow. Which are the consequences of po
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The population will continue to grow but as we grow so does pollution. Some would need vaccines to cure simple diseases like the flu but what if there would not be enough?
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In the diagram of a transverse wave shown, what does P represent?
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L is amplitude M is wavelength and P is frequency
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A 300-gallon anaerobic digester will be loaded daily with a feedstock that contains two parts dairy manure and one-part water by
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The volume of feedstock needed to mantain an organic load rate of 2 kgVS/day is 0.055 m3/day of feedstock.

The HRT is 20.6 days.

Explanation:

First, we calculate how many kg is 1 m3 of feedstock. We know the density, so we can calculate the mass:

M=\rho*V=37.5\frac{lb}{ft^3}*1m^3*(\frac{3.281ft}{1m})  ^3=1324.5lb=600.7 kg

If the VS are 6% in weight,

M_{vs}=0.06*M=0.06*600.7\,kg/m^3=36,0kgVS/m3

The volume per day needed to feed 2 kg of VS/day is:

V=\frac{2kg}{36kg/m^3}= 0.055m3/day=5.5litres/day

The HRT depends on the volume of the tank and the flow. Its equation is

HRT=\frac{V}{Q}=\frac{300gal}{0.055 m^3/day}*\frac{1m^3}{264.172gal}\\   \\HRT=20.6\,days

6 0
3 years ago
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