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prisoha [69]
2 years ago
13

Heat transfer through direct contact between molecules

Chemistry
1 answer:
kenny6666 [7]2 years ago
3 0

Answer:

This is an example of a form of energy transferring itself. Tons of electrons are passed through the energy itself to you very quickly. That's why when we touch a hot surface and get burned, it's because our skin molecules are touching the heat molecules.

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The bonds in the compound MgSO4 can be described asA. ionic, onlyB. covalent, onlyC. both ionic and covalentD. neither ionic nor
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Which statement is true about SO4 2− ?
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What mass of copper sulphate dissolves in 100g of water at 70 °C​
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Calculate the heat energy required to melt 4kg of ice when the specific latent heat of fusion of water is 334,000 J/kg.
Setler79 [48]

Taking into account the definition of calorimetry and latent heat, the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 \frac{J}{kg} is 1,336 kJ.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

<h3>Heat energy required to melt ice</h3>

In this case, you know:

  • m= 4 kg
  • L= specific latent heat of fusion of water= 334,000 \frac{J}{kg}

Replacing in the expression for latent heat:

Q = 4 kg× 334,000 \frac{J}{kg}

Solving:

<u><em>Q= 1,336,000 J= 1,336 kJ </em></u>(being 1,000 J= 1 kJ)

Finally, the correct answer is the first option: the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 \frac{J}{kg} is 1,336 kJ.

Learn more about calorimetry:

<u>brainly.com/question/14057615?referrer=searchResults</u>

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