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3 years ago

If the oxidation number of an atom decreases, the atom has undergone oxidation.

Chemistry

1 answer:

Bumek [7]3 years ago

8 0

Oxidation is a process when an atom, a group of atoms, or an ion loses electrons.

For example,

Cu⁰ -------> Cu⁺² + 2e⁻. This is an oxidation process.

As we can see an oxidation number was 0, and it became +2. The oxidation number is increased. Oxidation number of the atom, when an atom has undergone oxidation, increases.

So, answer is b.False.

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Two standard methods are used to express the relation between protein concentration and its absorbance at 280 nm. One of these m

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3 years ago

Listening to music on your headphones converts what energy to what energy

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I think it converts electrical energy to sound energy because, say if you're listening to music on your phone but, with the speaker on. The speaker of the phone on the other end changes the electrical energy/ electromagnetic waves back into sound energy. I believe the same goes with headphones

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3 years ago

The ratio of the specific heat of aluminum to the specific heat of iron is 2:1. How much energy must be transferred to the alumi

erastova [34]

Given what we know about ratios, we can confirm that in comparison to the iron pan, the aluminum pan will receive twice as much heat.

<h3>Why would the aluminum pan receive double the heat?</h3>

This has to do with the ratio being presented.
A ratio of 2:1 means that for every unit of heat to the iron, the aluminum receives 2.
In other words, the aluminum pan receives twice as much heat when compared to the iron pan.

Therefore, we can confirm that because the ratio of heat to the aluminum in comparison to the iron pan is 2:1, this means that for every 1 unit of heat to the iron pan, the aluminum pan will receive 2. This results in double the total heat received by the aluminum pan.

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2 years ago

A 10.11 g sample of NaBr contains 22.34 % Na by mass. Considering the law of constant composition (definite proportions), how ma

Ksenya-84 [330]

Answer:

$1.58\ \text{g}$

Explanation:

10.11 g sample of $NaBr$ contains 22.34% $Na$ by mass

According to the law of constant composition the if one sample of $NaBr$ has 22.34% of $Na$ by mass then any other sample of $NaBr$ will have the same percentage of the amount of $Na$ .

For a sample of 7.09 g we have

$7.09\times \dfrac{22.34}{100}=1.583906\approx 1.58\ \text{g}$

The mass of sodium in the required sample is $1.58\ \text{g}$ .

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3 years ago

Object A specific heat is 2.45 J/g C and object B specific heat is 0.82 J/g C. Which object will heat up more if they have the s

Artist 52 [7]

Answer: Object B will heat up more.

Explanation:

The formula for specific heat is as follows.

Q = $m C \Delta T$

Where,

Q = heat provided

m = mass

C = specific heat

$\Delta T$ = change in temperature

Now, both the objects have same mass and equal amount of heat is applied.

According to the formula, the equation will be as follows.

$Q_{1}$ = $Q_{2}$

$m C_{1}\Delta T$ = $m C_{2}\Delta T_{2}$

Cancel m from both sides, as mass is same. Therefore,

$C_{1} (T_{f} - T_{i})_A$ = $C_{2}(T_{f} - T_{i})_B$

Cancel out the initial temperature and put the values of specific heat, then the equation will be as follows.

$2.45 (T_{f})_A$ = $0.82(T_{f})_B$

Therefore, from the above equation it can be concluded that the object with low specific heat will heat up more as its specific heat will be inversely proportional to its final temperature.

Hence, object B will heat up more.

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3 years ago