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andrew11 [14]
2 years ago
12

Click this link to view O*NET’s Work Styles section for Postal Service Mail Carriers. (Common work styles are listed near the to

p and less-common work styles are near the bottom.) According to O*NET, which common work styles do Postal Service Mail Carriers need? Select four options.
dependability
creativity
leadership
integrity
self-control
attention to detail
Physics
1 answer:
zmey [24]2 years ago
7 0

The common work styles do Postal Service Mail Carriers need creativity, integrity, self-control and attention to detail.

<h3>
What is postal mail service carriers?</h3>

They commonly sort mail and orchestrate it arranged by their conveyance course. They convey the mail by walking or any vehicle. They also gather mail and convey it to the post office. Mail transporters answer clients inquiries, provide forms, and look out for surprising conditions on their course.

Thus, the common workstyles they should need to have are creativity, integrity, self-control and attention to detail.

Learn more about postal mail service carriers.

brainly.com/question/23310980

#SPJ1

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PLS PLS PLS PLS PLS PLS PLS PLS PLS HELP FREE POINTS
Ne4ueva [31]

Answer:

see below

Explanation:

First: Leave a couple inches of wire loose at one end and wrap most of the rest of the wire around iron  u-shaped bar and make sure not to overlap the wires.

Second:Cut the wire (if needed) so that there is about a couple inches loose at the other end too.

Third: Now remove about an inch of the plastic coating from both ends of the wire and connect the one wire to one end of a battery and the other wire to the other end of the battery.

3 0
3 years ago
Suppose a soccer player kicks the ball from a distance 29 m toward the goal. find the initial speed of the ball if it just passe
Rudik [331]

The ball's vertical velocity at the time it just passes over the goal is 0 m/s. Its initial vertical velocity is unknown and we denote it by v\sin39^\circ, where v here is the ball's initial speed. Vertically, the only force acting on the ball is gravity, which attributes a downward acceleration of 9.8 m/s^2. We expect the maximum height achieved by the ball to be 2.4 m, so we can find the initial speed by solving

\left(0\,\dfrac{\mathrm m}{\mathrm s}\right)^2-\left(v\sin39^\circ\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm m)

\implies v=11\,\dfrac{\mathrm m}{\mathrm s}

6 0
3 years ago
A lamp consumes 1000J of ekectrical energy in 10s. Calculate its power.​
Mice21 [21]
You do 1000 divide it by 10 which equals 100 W
4 0
3 years ago
What is the calculation for elastic potential?
grin007 [14]
Elastic potential energy is equal to the force times the distance of movement. Elastic potential energy = force x distance of displacement. Because the force is = spring constant x displacement, then the Elastic potential energy = spring constant x displacement squared.
3 0
3 years ago
At the same moment, one rock is dropped and one is theown downwand with an iniial velocily of 29 us frm op of a building that is
Helen [10]

Answer:

The thrown rock will strike the ground 2.42s earlier than the dropped rock.

Explanation:

<u>Known Data</u>

  • y_{i}=300m
  • y_{f}=0m
  • v_{iD}=0m/s
  • v_{iT}=-29m/s, it is negative as is directed downward

<u>Time of the dropped Rock</u>

We can use y_{f}=y_{i}+v_{iy}t-\frac{gt^{2}}{2}, to find the total time of fall, so 0=300m-\frac{(9.8m/s^{2})t_{D}^{2}}{2}, then clearing for t_{D}.

t_{D}=\sqrt[2]{\frac{300m}{4.9m/s^{2}}} =\sqrt[2]{61.22s^{2}} =7.82s

<u>Time of the Thrown Rock</u>

We can use y_{f}=y_{i}+v_{iy}t-\frac{gt^{2}}{2}, to find the total time of fall, so 0=300-29t_{T}-\frac{(9.8)t_{T}^{2}}{2}, then, 0=-4.9t_{T}^{2}-29t_{T}+300, as it is a second-grade polynomial, we find that its positive root is t_{T}=5.4s

Finally, we can find how much earlier does the thrown rock strike the ground, so t_{E}=t_{D}-t_{T}=7.82s-5.4s=2.42s

6 0
3 years ago
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