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igomit [66]
2 years ago
9

The gravitational force between two volleyball players is 3.3x10^-7.

Physics
1 answer:
Pepsi [2]2 years ago
5 0

The distance of separation between the two masses is 0.927 m.

<h3>Gravitational force:</h3>

This is the force that exists between two masses in the universe.

To calculate the distance of separation of the masses, we use the formula below.

  • F = GMm/r².............. Equation 1

Where:

  • F = Gravitational force
  • m = First mass
  • M = Second mass
  • G = Universal constant
  • r = distance of seperation.

Make r the subject of the equation.

  • r = √(GMm/F)................... Equation 2

From the question,

Given:

  • F = 3.3×10⁻⁷ N
  • m = 61 kg
  • M = 75 kg
  • G = 6.69×10⁻¹¹ Nm²/kg²

Substitute these values into equation 2

  • r = √(61×75×6.69×10⁻¹¹)/(3.3×10⁻⁷)
  • r = 0.927 m

Hence, The distance of separation between the two masses is 0.927 m

Learn more about Gravitational force here: brainly.com/question/11359658

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3 years ago
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The mean may be calculated by summing the values of the refractive index and dividing the sum by the number of experiments. This is:
Mean = (1.45 + 1.56 + 1.54 + 1.44 + 1.54 + 1.53)/6
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The mean absolute error is the sum of the absolute values of errors divided by the number of trials:
MAE = (|1.45-1.51|+|1.56-1.51|+|1.54-1.51|+|1.44-1.51|+|1.54-1.51|+|1.53-1.51|)/6
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The fractional error is the MAE divided by the actual value:
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The percentage error is the fractional error multiplied by 100:
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