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igomit [66]
2 years ago
9

The gravitational force between two volleyball players is 3.3x10^-7.

Physics
1 answer:
Pepsi [2]2 years ago
5 0

The distance of separation between the two masses is 0.927 m.

<h3>Gravitational force:</h3>

This is the force that exists between two masses in the universe.

To calculate the distance of separation of the masses, we use the formula below.

  • F = GMm/r².............. Equation 1

Where:

  • F = Gravitational force
  • m = First mass
  • M = Second mass
  • G = Universal constant
  • r = distance of seperation.

Make r the subject of the equation.

  • r = √(GMm/F)................... Equation 2

From the question,

Given:

  • F = 3.3×10⁻⁷ N
  • m = 61 kg
  • M = 75 kg
  • G = 6.69×10⁻¹¹ Nm²/kg²

Substitute these values into equation 2

  • r = √(61×75×6.69×10⁻¹¹)/(3.3×10⁻⁷)
  • r = 0.927 m

Hence, The distance of separation between the two masses is 0.927 m

Learn more about Gravitational force here: brainly.com/question/11359658

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An object with a mass of 70 kilograms is supported at a height of 8 meters above the ground, what's the potential energy of the
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5488 Joules

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Calculate the angle of refraction of 30.0° light shines from water into ice. The indices of refraction for water and ice are 1.3
WITCHER [35]

Answer:

The angle of refraction Ø2 equals 62.95° ≈ 63°

Explanation:

The relationship between the angles of incidence and

refraction , with respect to light or other waves passing through two different substances or media, such as glass, water or air is given by Snell's Law.

Snell's Law states that the when light travels from one medium to another, it generally refracts.

It is given by the mathematical expression;

[SinØ1°/SinØ2°] = [n2/n1]

Cross multiplying, we have;

n1 × SinØ1° = n2 × SinØ2°

where, n is the indices of refraction of each substance

Ø is the angle between the ray and the line normal to the surface.

Given the following values;

n1 = 1.36 n2 = 1.31 Ø1 = 30° Ø = ?

n1 × SinØ1° = n1 × SinØ2°

SinØ2° = [n1 × SinØ1°]/n2

substituting the values respectively;

SinØ2° = [1.36 × Sin30°]/1.31

SinØ2° = [1.36 × 0.5]/1.31

SinØ2° = 0.68 × 1.31

SinØ2° = 0.8906

Ø2° = Sin–¹(0.8906)

Ø2° = 62.95° ≈ 63°

4 0
3 years ago
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