Answer:
X = 15.88 m
Explanation:
Given:
Initial Velocity V₀ = 13.4 m/s
θ = 30.1 °
g = 9.8 m/s²
To Find horizontal distance let "X" we have to time t first.
so from motion 2nd equation at Height h = 0
h = V₀y t + 1/2 (-g) t ² (ay = -g)
0 = 13.4 sin 30.1° t - 0.5 x 9.81 x t² (V₀y = V₀ Sin θ)
⇒ t = 1.37 s
Now For Horizontal distance X, ax =0m/s²
X = V₀x t + 1/2 (ax) t ²
X = 13.4 m × cos 30.1° x 1.37 s + 0
X = 15.88 m
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B.yellow-white is the answer.
The rate of energy radiated by the man is 3.86 x
J/s.
.
The amount of energy radiated by an object majorly depends on the area of its surface and its temperature. The is well explained in the Stefan-Boltzmann's law which states that:
Q(t) = Aeσ
where: Q is the quantity of heat radiated, A is the surface area of the object, e is the emmisivity of the object, σ is the Stefan-Boltzmann constant and T is the temperature of the object.
To determine the rate of energy radiated by the man in the given question;
= Aeσ
But A = 1.7 m², e = 0.4 and σ = 5.67 x
J/s.
So that;
= 1.7 * 0.4 * 5.67 x
= 3.8556 x
= 3.86 x
J/s. 
Thus, the rate of energy radiated by the man is 3.86 x
J/s.
.
Learn more on energy radiation of objects by visiting: brainly.com/question/12550129