A drill has a density of 11.342 g/cm3. Its mass is 1500 g. What is the volume of the drill? Round to TWO decimal places.

all but which of the following might cause a tsunami? a. volcanic eruption b. flooding c. landslide d. earthquake

LUCKY_DIMON [66]

I believe the answer to ur questions is b.) flooding

4 0

3 years ago

Read 2 more answers

What is the term that describes<br> the material through which a wave travels?

Genrish500 [490]

Answer:

A WAVE IS ANY DISTURBANCE THAT TRANSMITS ENERGY THROUGH MATTER OR SPACE. ... HOWEVER, THE MATERIAL THROUGH WHICH THE WAVE TRAVELS DOES NOT MOVE WITH THE ENERGY. A MEDIUM IS A SUBSTANCE THROUGH WHICH A WAVE CAN TRAVEL. A MEDIUM CAN BE A SOLID, A LIQUID, OR A GAS.

i hope this is helpful :)

Explanation:

3 0

3 years ago

Hi can you help me with this please?

bagirrra123 [75]

Answer:

4s

Explanation:

My assumption would be 4s since 25 going into 100 would be 4? hope that helped..

5 0

3 years ago

The kinetic energies of particles in a sample of matter are increasing. This sample is most likely

KIM [24]

gaining thermal energy in form of heat

Explanation:

When the thermal energy of a matter is increasing, it will directly increase the kinetic energy of the matter.

Temperature changes causes the average kinetic energy of molecules to increase or decrease.
If the kinetic energies of particles are increasing, the temperature must have been on rise.
Increase in temperature causes molecules to start vibrating and moving about.
The gain more energy that helps them to move away from their original position

Learn more:

Kinetic energy brainly.com/question/7966903

#learnwithBrainly

8 0

3 years ago

A sphere moves in simple harmonic motion with a frequency of 4.80 Hz and an amplitude of 3.40 cm. (a) Through what total distanc

geniusboy [140]

Answer:

a) the total distance traveled by the sphere during one cycle of its motion = 13.60 cm

b) The maximum speed is = 102.54 cm/s

The maximum speed occurs at maximum excursion from equilibrium.

c) The maximum magnitude of the acceleration of the sphere is = 30.93 $m/s^2$

The maximum acceleration occurs at maximum excursion from equilibrium.

Explanation:

Given that :

Frequency (f) = 4.80 Hz

Amplitude (A) = 3.40 cm

a)

The total distance traveled by the sphere during one cycle of simple harmonic motion is:

d = 4A (where A is the Amplitude)

d = 4(3.40 cm)

d = 13.60 cm

Hence, the total distance traveled by the sphere during one cycle of its motion = 13.60 cm

b)

As we all know that:

$x = Asin \omega t$

Differentiating the above expression with respect to x ; we have :

$\frac{d}{dt}(x) = \frac{d}{dt}(Asin \omega t)$

$v = A \omega cos \omega t$

Assuming the maximum value of the speed(v) takes place when cosine function is maximum and the maximum value for cosine function is 1 ;

Then:

$v_{max} = A \omega$

We can then say that the maximum speed therefore occurs at the mean (excursion) position where ; x = 0 i.e at maximum excursion from equilibrium

substituting $2 \pi f$ for $\omega$ in the above expression;

$v_{max} = A(2 \pi f)$

$v_{max} = 3.40 cm (2 \pi *4.80)$

$v_{max} = 102.54 \ cm/s$

Therefore, the maximum speed is = 102.54 cm/s

The maximum speed occurs at maximum excursion from equilibrium.

c) Again;

$v = A \omega cos \omega t$

By differentiation with respect to t;

$\frac{d}{dt}(v) = \frac{d}{dt}(A \omega cos \omega t)$

$a =- A \omega^2 sin \omega t$

The maximum acceleration of the sphere is;

$a_{max} =A \omega^2$

where;

$w = 2 \pi f$

$a_{max} = A(2 \pi f)^2$

where A= 3.40 cm = 0.034 m

$a_{max} = 0.034*(2 \pi *4.80)^2$

$a_{max} = 30.93 \ m/s^2$

The maximum magnitude of the acceleration of the sphere is = 30.93 $m/s^2$

The maximum acceleration occurs at maximum excursion from equilibrium where the oscillating sphere will have maximum acceleration at the turning points when the sphere has maximum displacement of $x = \pm A$

6 0

3 years ago