Please Help me! This is a EOC Review. Delta Math!
2 answers:
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The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at (-1.5, -3.25).
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For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at (-1.5, -3.25).
_____
For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
<h3>Answer: (2, 2)</h3>
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Explanation:
The phrasing "translated along <4,6>" is another way of saying "shift 4 to the right, shift 6 up"
In general, "translated along <m,n>" is the same as writing . If m is positive, then we shift m units to the right. If m is negative, then we shift to the left. The same story happens with the n, but we focus on the y coordinate.
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With all that in mind, starting at F(-5,-9) and translating along <4,6> has us arrive at (-1, -3). Add 4 to the x coordinate and add 6 to the y coordinate.
We can say
Showing that (-5,-9) moves to (-1,-3)
This is after the first translation, but there's a second translation.
We'll apply the same idea, but different numbers this time
So (-1,-3) moves to (2,2)
Overall we have
- (-5,-9) move to (-1,-3) after the first translation
- (-1,-3) move to (2,2) after the second translation
Therefore, the original point ends up at (2,2) which is the final answer
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Extra info:
A nice shortcut is that the vectors <4,6> and <3,5> can be added to get <4+3,6+5> = <7,11>. So overall, we're shifting 7 units to the right and 11 units up when we combine the two translation vectors.