PLEASE HELPP PLEASE find the zeros and factored form of c(x)=3x^2-3
2 answers:
Answer:
see explanation
Step-by-step explanation:
Given
c(x) = 3x² - 3 ← factor out 3 from each term
= 3(x² - 1) ← x² - 1 is a difference of squares
= 3(x - 1)(x + 1) ← in factored form
To find the zeros equate c(x) to zero, that is
3(x - 1)(x + 1) = 0
Equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
x - 1 = 0 ⇒ x = 1
zeros are x = - 1, x = 1
Answer:
3 ( x-1) (x+1) is the factored form
zeros are x=1, -1
Step-by-step explanation:
3x^2-3
Factor out a 3
3 ( x^2 -1)
What is inside the parentheses is the difference of squares
( a^2 -b^2) = ( a-b)(a+b)
3 ( x-1) (x+1)
To find the zeros, set this equal to zero
3 ( x-1) (x+1) =0
Using the zero product property
x-1 =0 x+1 =0
x=1, x=-1
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