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fiasKO [112]
2 years ago
15

The chart shows the times and accelerations for three drivers.

Physics
1 answer:
aliina [53]2 years ago
6 0

The lists from greatest to lowest change in velocity.Dustin → Diego → Kira. Option A is correct.

<h3 /><h3>What is acceleration?</h3>

The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The acceleration is obtained one by one from the given data as the ratio of the velocity to the time.

For the acceleration of each, you can refer to the excel table attached below.

The velocity changes are listed from largest to least. Dustin and Diego Kira.

Hence, option A is the right answer.

To learn more about acceleration, refer to the link;

brainly.com/question/2437624

#SPJ1

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A person walking in high heals can damages the floor by making small dimples in the floor since all their weight is concentrated
iren [92.7K]

Given :

Mass of person, m = 81 kg.

Area of high heal, A = 3.5 cm² = 0.00035 m².

To Find :

The pressure applied by the heal on the ground.

Solution :

We know, pressure is given by :

P = \dfrac{mass}{Area}\\\\P = \dfrac{81}{0.00035} \ N/m^2\\\\P = 231428.57 \ N/m^2

Hence, this is the required solution.

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3 years ago
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4 0
3 years ago
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The odometer of a car reads 57321 km when the clock shows the time 8.30 am. What is the distance moved by the car, if at 8.50 am
malfutka [58]

Answer:

0.75km/min

Explanation:

I haven't learnt physics at all but I'll try

57336 - 57321 = 15km (Difference)

8.50 am - 8.30 am = 20 minutes (Difference)

If the car odometer adds up 15km every 20 minutes...

20 mins = 15km

1 min = 15 ÷ 20 = 0.75km

3 0
3 years ago
Two blocks with masses 1 and 2 are connected by a massless string that passes over a massless pulley as shown. 1 has a mass of 2
Bess [88]

Answer:

The acceleration of M_2 is  a =  0.7156 m/s^2

Explanation:

From the question we are told that

    The mass of first block is  M_1 =  2.25 \ kg

    The angle of inclination of first block is  \theta _1 =  43.5^o

    The coefficient of kinetic friction of the first block is  \mu_1  = 0.205

      The mass of the second block is  M_2 = 5.45 \ kg

     The angle of inclination of the second block is  \theta _2 =  32.5^o

      The coefficient of kinetic friction of the second block is \mu _2 = 0.105

The acceleration of M_1 \ and\  M_2 are same

The force acting on the mass M_1 is mathematically represented as

     F_1 = T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1

=> M_1 a = T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1

Where T is the tension on the rope

The force acting on the mass M_2 is mathematically represented as    

  F_2 =  M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

   M_2 a =  M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

At equilibrium

  F_1 =  F_2

So

 T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1 =M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

making a the subject of the formula

    a =  \frac{M_2 g sin \theta_2 - M_1 g sin \theta_1 - \mu_1 M_1g cos \theta - \mu_2 M_2 g cos \theta_2 }{M_1 +M_2}

substituting values a =  \frac{(5.45) (9.8) sin (32.5) - (2.25) (9.8) sin (43.5) - (0.205)*(2.25) *9.8cos (43.5) - (0.105)*(5.45) *(9.8) cos(32.5) }{2.25 +5.45}

    => a =  0.7156 m/s^2

     

3 0
4 years ago
What is the displacement from 4 to 10 seconds? How do you know?
Strike441 [17]
For velocity vs time graphs, you can calculate displacement by finding the area between the line and the x-axis (time line). You should be able to recognize that space between the lines as a triangle, trapezoid, square, or rectangle and use the respective area formulas for these shapes.

See attached photo for worked out solution.

4 0
4 years ago
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