Answer:
Explanation:
In this case we shall calculate rate of change of flux in the coli to calculate induced emf .
Flux through the coil = no of turns x area x magnetic field perpendicular to it
=34 x 2.25 x (3.95 )²x 10⁻⁴ Weber
= 1193.4 x 10⁻⁴Weber
Final flux through the coil after turn by 90°
= 1193.4 x 10⁻⁴ cos 90 ° =0
Change of flux
= 1193.4 x 10⁻⁴ weber.
Time taken = 0.335 s .
Average emf= Rate of change of flux
= change in flux / time
=1193.4 x 10⁻⁴ / .335
= 3562.4 x 10⁻⁴
356.24 x 10⁻³
=356.24 mV.
Current induced = emf induced / resistance
= 356.24/.780
= 456.71 mA.
Answer:
v = √ 2e (V₂-V₁) / m
Explanation:
For this exercise we can use the conservation of the energy of the electron
At the highest point. Resting on the top plate
Em₀ = U = -e V₁
At the lowest point. Just before touching the bottom plate
Emf = K + U = ½ m v² - e V₂
Energy is conserved
Em₀ = Emf
-eV₁ = ½ m v² - e V₂
v = √ 2e (V₂-V₁) / m
Where e is the charge of the electron, V₂-V₁ is the potential difference applied to the capacitor and m is the mass of the electron
Answer:
Time=15,Mass=3,Acceleration due to gravity=10,Height=50,Power=?.
Power=mgh/t.....which is 3×10×50=1500/15=100Watts.
Answer:
a) Energy density of the magnetic field, u = 183.46 J/m³
b) Total energy, E = 0.167 J
Explanation:
a) Number of turns in the solenoid, N = 1410
Area, A = 13.8 cm² = 0.00138 m²
Current, I = 8.01 A
Length of the solenoid, l = 66.1 cm = 0.661 m
Energy density, u is given by the formula 
Where B is the magnetic field
The magnetic field in a solenoid is given by the formula, 

T

b) The total energy = Energy density * Volume
E = u V
Volume = Area * Length
V = Al = 0.00138 * 0.661
V = 0.00091218 m³
E = 183.46 * 0.00091218
E = 0.167 J