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3 years ago

In a school thereare 160 boys to number of girls is 2:3how many girls there are

Mathematics

2 answers:

Aleksandr [31]3 years ago

8 0

Answer:

240 girls

Step-by-step explanation:

Let number of girls be x.

160:x = 2:3

Multiply right side by 80--> 160:x = 160:240

x=240.

So there are 240 girls.

Contact [7]3 years ago

4 0

Answer:

There should be 240 girls.

Step-by-step explanation:

Ultimately, you want 40% of the school to be boys and 60% of the school to be girls which equal to the ratio 2:3. Divide 160 by 2 to get 80 for the first part of the ratio, then you should multiply that number by 3 to get 240 as the number of girls in that school.

The ratio should be 160:240 when you put the number of boys and girls in this situation.

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How do you write 9.6004 × 10^15 in standard form?

Naddik [55]

Answer:

9600400000000000 is in standard form

6 0

2 years ago

Use Pascal's Triangle to determine the second term of the expansion of (x - 2)^5

goldfiish [28.3K]

Pascal's triangle up to the 5th iteration is

$\begin{array}{cccccc}1\\1&1\\1&2&1\\1&3&3&1\\1&4&6&4&1\\1&5&10&10&5&1\end{array}$

This tells us

$(x-2)^5=\boxed{1}x^5(-2)^0+\boxed{5}x^4(-2)^1+\boxed{10}x^3(-2)^2+\boxed{10}x^2(-2)^3+\boxed{5}x^1(-2)^4+\boxed{1}x^0(-2)^5$

so the second term in the expansion is

$5x^4(-2)^1=\boxed{-10x^4}$

8 0

3 years ago

Consider a normal distribution curve where the middle 85 % of the area under the curve lies above the interval ( 8 , 14 ). Use t

NeTakaya

Answer:

$\mu = 11$

$\sigma = 2.08$

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Middle 85%.

Values of X when Z has a pvalue of 0.5 - 0.85/2 = 0.075 to 0.5 + 0.85/2 = 0.925

Above the interval (8,14)

This means that when Z has a pvalue of 0.075, X = 8. So when $Z = -1.44, X = 8$ . So