The ostrich runs 21 N then goes back by 25 S
The displacement is -4 S
21 - 25 = -4
Answer:
Calcium carbonate and citric acid.
Explanation:
Hello!
In this case, considering the text, we can notice that calcium carbonate combines with citric acid to produce the calcium citrate water and carbon dioxide as shown on the following equation:
![3CaCO_3+2C_6H_8O_7\rightarrow Ca_3C_{12}H_{10}O_{14}+CO_2+H_2O](https://tex.z-dn.net/?f=3CaCO_3%2B2C_6H_8O_7%5Crightarrow%20Ca_3C_%7B12%7DH_%7B10%7DO_%7B14%7D%2BCO_2%2BH_2O)
Whereas the reactants, at the left side, are identified as calcium carbonate and citric acid.
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Answer: The starting pressure of
is 1.39 atm.
Explanation:
![CCl_4\rightleftharpoons C(s)+ 2Cl_2](https://tex.z-dn.net/?f=CCl_4%5Crightleftharpoons%20C%28s%29%2B%202Cl_2)
Initial p 0 0
eq'm p-x 0 2x
Total pressure at equilibrium = p - x + 2x = p + x = 1.9...(1)
![K_p=0.76=\frac{p_{C}\times p^2_{Cl_2}}{p_{CCl_4}}=\frac{0\times(2x)^2}{p-x}](https://tex.z-dn.net/?f=K_p%3D0.76%3D%5Cfrac%7Bp_%7BC%7D%5Ctimes%20p%5E2_%7BCl_2%7D%7D%7Bp_%7BCCl_4%7D%7D%3D%5Cfrac%7B0%5Ctimes%282x%29%5E2%7D%7Bp-x%7D)
...(2)
Solving equation (1) and (2). we get x = 0.51
p + x = 1.9
p= 1.9 - 0.51 = 1.39 atm
The starting pressure of
is 1.39 atm.
Answer:
True
Explanation:
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Mass of AlCl₃ : 93.39 g
<h3>Further explanation</h3>
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
![\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BM%20~%20%3D%20~%20%5Cdfrac%20%7Bn%7D%20%7BV%7D%7D%7D)
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So to find the number of moles can be expressed as
n = V x M
the volume of the solution = 330 cm³=0.33 dm³
the concentration of the solution = 283 g/dm³
mass of AlCl₃ :
![\tt mass=V\times M\\\\mass=0.33\times 283=93.39~g](https://tex.z-dn.net/?f=%5Ctt%20mass%3DV%5Ctimes%20M%5C%5C%5C%5Cmass%3D0.33%5Ctimes%20283%3D93.39~g)