Identify the gas law that applies to the following scenario: If a gas in a closed container is pressurized from 18.0 atm to 14.0
atm and its original
temperature was 35.0°C, what would the final temperature of the gas be?
Charles' Law
O Avogadro's Law
O Boyle's Law
O Gay-Lussac's Law
temperature was 35.0°C, what would the final temperature of the gas be?
Charles' Law
O Avogadro's Law
O Boyle's Law
O Gay-Lussac's Law
1 answer:
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Explanation:
Molar mass of = 39.1 + 35.5 + 3(16.0) = 122.6 g
Molar mass of KCl = 39.1 + 35.5 = 74.6 g
Molar mass of = 32.0 g
According to the equation, 2 moles of reacts to give 3 moles of oxygen.
Therefore, 2 (122.6) = 245.2 g of will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of
gives 96.0 g of oxygen.
(a) Calculate the amount of oxygen given by 2.72 g of as follows.
of
(b) Calculate the amount of oxygen given by 0.361 g of as follows.
of
c) Calculate the amount of oxygen given by 83.6 kg as follows.
of
Convert kg into grams as follows.
= 32731 g of
(d) Calculate the amount of oxygen given by 22.5 mg of as follows.
Convert mg into grams as follows.
of