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3 years ago

Interpreting Velocity vs. Time Graphs

Chemistry

1 answer:

NemiM [27]3 years ago

4 0

Answer:first part is A and C, second part is C, third part is 40 m/s and the fourth part is zero

Explanation: I guessed and got them right lol

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How many neutrons does the isotope N-14 have? 6 7 8 9

hodyreva [135]

Answer:

THe answer is 7

Explanation:

I took the Quiz/Test

7 0

3 years ago

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If 22.5 mol of an ideal gas occupies 30.5 L at 447 K, what is the pressure of the gas?

Fantom [35]

Answer:

P = 27.07 atm

Explanation:

Given that,

The number of moles, n = 22.5 mol

Volume, V = 30.5 L

Temperature, T = 447 K

We need to find the pressure of the gas. The ideal gas law is as follows :

$PV=nRT\\\\P=\dfrac{nRT}{V}$

R = 0.0821 L-atm/mol-K

Put all the values,

$P=\dfrac{22.5\times 0.0821\times 447}{30.5}\\\\P=27.07\ L$

So, the pressure of the gas is 27.07 atm.

8 0

3 years ago

Which statements accurately describe electronic tools? Check all that apply.

kipiarov [429]

e.g. pliers, cutters, crimps, wire wrapping tools, etc., if youre meaning electronic hand tools

5 0

4 years ago

Read 2 more answers

a rectangular piece of aluminum foil measures 13.72 cm x 8.63 cm and has a mass of 3.1 g. Find how thick it is

Leona [35]

The two dimensions of aluminum foil are given 13.72 cm and 8.63 cm respectively with mass 3.1 g.

The density of aluminum is $2.7 g/cm^{3}$ . It is defined as mass per unit volume thus, volume of aluminum can be calculated as follows:

$V=\frac{m}{d}$

Putting the values.

$V=\frac{3.1 g}{2.7 g/cm^{3}}=1.148 cm^{3}$

The volume of cuboid is $l\times b\times h$ , the length and breadth are given, height can be calculated as follows;

$h=\frac{V}{l\times b}$

Putting the values,

$h=\frac{1.148 cm^{3}}{(13.72 cm)(8.63 cm)}=0.009695 cm$

Or, approximately 9.7\times 10^{-3}cm

Therefore, thickness of aluminum foil is $9.7\times 10^{-3}cm$

7 0

3 years ago

What weight of sodium formate must be added to 4.00L of 1.00 M formic acid to produce a buffer solution that has a pH of 3.50?

tester [92]

Answer:

156,4 g of sodium formate

Explanation:

The pka of the formic acid is 3,74. Using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [A⁻] / [HA] (1)

Where A⁻ is the conjugate base (Formate) and HA is the formic acid.

4.00L of 1.00M formic acid contain:

4.00L × (1.00mol /L) = 4.00 moles

Replacing these moles, the desired pH and the pka value in (1):

3,50 = 3,74 log₁₀ [A⁻] / 4,00 moles

-0,24 = log₁₀ [A⁻] / 4,00 moles

0,575 = [A⁻] / 4,00 moles

2,30 moles = [A⁻]

That means you need 2,30 moles of formate (Sodium formate), to produce the desired buffer. As the molar mass of sodium formate is 68,01g/mol, the weight of sodium formate that must be added is:

2,30mol×(68,01g/mol) = 156,4 g of sodium formate.

I hope it helps!

7 0

3 years ago