The height in feet of the missile after 5 seconds in the air is; 875 ft
<h3>How to find the height of a Projectile?</h3>
We are given the quadratic function of the height in terms of time, x, in seconds as; h(x) = - 17x² + 260x
where;
h(x) is height after x seconds
x seconds is time of missile in air when thrown.
Thus, after five seconds, we have;
h(5) = - 17(5)² + 260(5)
h(5) = -425 + 1300
h(5) = 875 feet
Complete question is;
A missile is launched from the ground. Its height, h(x), can be represented by a quadratic function in terms of time, x, in seconds.
After 1 second, the missile is 243 feet in the air; after 2 seconds, it is 452 feet in the air.
The height of the can be represented by this function:
h(x) = - 17x² + 260x
Find the height, in feet, of the missile after 5 seconds in the air.
Read more about Projectiles at; brainly.com/question/1130127
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