Question

Find the height in feet of the missile after 5 seconds in the air

Answer 1

The height in feet of the missile after 5 seconds in the air is; 875 ft

How to find the height of a Projectile?

We are given the  quadratic function of the height in terms of time, x, in seconds as; h(x) = - 17x² + 260x

where;

h(x) is height after x seconds

x seconds is time of missile in air when thrown.

Thus, after five seconds, we have;

h(5) = - 17(5)² + 260(5)

h(5) = -425 + 1300

h(5) = 875 feet

Complete question is;

A missile is launched from the ground. Its height, h(x), can be represented by a quadratic function in terms of time, x, in seconds.

After 1 second, the missile is 243 feet in the air; after 2 seconds, it is 452 feet in the air.

The height of the can be represented by this function:

h(x) = - 17x² + 260x

Find the height, in feet, of the missile after 5 seconds in the air.

Read more about Projectiles at; brainly.com/question/1130127

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