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Karo-lina-s [1.5K]
2 years ago
14

Compute. 5/34 x 22 2/3 - 2 1/9

Mathematics
2 answers:
Sav [38]2 years ago
7 0
1.222 repeating is the answer
maxonik [38]2 years ago
5 0
Answers is 11/9 or decimal form is 1.222 repeating
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the perimeter of a rectangle is 50 inches. The length of the rectangle is 10 inches. What method can be used to find the width o
Vinil7 [7]

Answer:

P= 2(l+w)

50=2(10+w)

50=20+2w

50-20=2w

30=2w

w=15

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Step-by-step explanation:

6 0
2 years ago
Suppose you're making a soup that uses 5 cups of chicken broth and 3⁄4 teaspoons of corn starch for 8 servings. You need to make
yanalaym [24]

Answer:

Option A = 7.5 cups

Step-by-step explanation:

Given : Suppose you're making a soup that uses 5 cups of chicken broth and \frac{3}{4} teaspoons of corn starch for 8 servings. You need to make 12 servings of the soup, so you'll need 1\frac{1}{8} teaspoons of corn starch.

To find : How much broth do you need?

Solution :

A soup that uses 5 cups of chicken broth and \frac{3}{4} teaspoons of corn starch for 8 servings.

i.e. 5 cups + \frac{3}{4} teaspoon = 8 servings  ......(1)

You need to make 12 servings of the soup, so you'll need 1\frac{1}{8}=\frac{9}{8}

i.e. x cups +\frac{9}{8} teaspoon = 12 servings  ........(2)

So, First we find the ratio

Ratio is \frac{12}{8}=\frac{3}{2}

So to equal the ratio multiply (1) by \frac{3}{2}

5\times \frac{3}{2}cups + \frac{3}{4}\times \frac{3}{2} teaspoon = 8\times \frac{3}{2} servings

\frac{15}{2}cups + \frac{9}{8} teaspoon = 12 servings

On comparing with (2),

The value of x is \frac{15}{2}.

Therefore, The broth do we need is \frac{15}{2}=7.5 cups.

So, Option A is correct.

5 0
3 years ago
GIVING BRAINLIESTTTTT
andreev551 [17]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

# Contracting parallel lines

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2. Place the pin of the compass at point C and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

# Constructing a perpendicular line through a point on the line

- Given line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3. Place the compass pin on point C and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

* Lets find the same steps in the constructions

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  "Place the compass on a point on the original line"

6 0
3 years ago
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