Question

Please help...to answer all these questions pleaseeeee

Answer 1

Answer:

Part A) x co-ordinate is -4

Part B) x =1 and y = 2

Step-by-step explanation:

Part A

Given:

Two equations are given.

$y = -\frac{2}{3} x$

$4x-9y=-40$-----------(1)

Substitute $y = -\frac{2}{3} x$-in equation 1

$4x-9(-\frac{2}{3} x)=-40$

$4x-(-\frac{2\times 9}{3} x)=-40$

$4x-(-2\times 3 x)=-40$

$4x-(-6x)=-40$

Apply rule $-(-a)=a$

$4x+6x=-40$

$10x=-40$

$x=-\frac{40}{10}$

x=-4

Therefore, the coordinate of x is -4

Part B

Given:

Two equations are given:

$-5=x-3y$-------(1)

$11=-3x+7y$---------(2)

solve equation 1

$-5=x-3y$

$x=3y-5$----------(3)

substitute $x=3y-5$ in equation 2.

$11=-3(3y-5)+7y$

$11=-(9y-15)+7y$

$11=-9y+15+7y$

$11-15=-9y+7y$

$-4=-2y$

$4=2y$

$y=\frac{4}{2}$

y = 2

Now, we substitute y = 2 in equation 3.

$x=3(2)-5$

$x=6-5$

x = 1

Therefore, The value of y =2 and x = 1