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Marizza181 [45]

2 years ago

10

a covalent bond between two different atoms in which the bonding is not shared equally is a a) polar bond b) non polar bond c) i

onic bond d) hydrogen bond

1 answer:

makkiz [27]2 years ago

6 0

Answer:

polar bond

Explanation:

This is the definition of a polar bond.

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Elementler kimyasal özelliklerine göre, metaller, yan

Mashcka [7]

Answer:

d

Explanation:

5 0

3 years ago

HELP ME, HOW? Draw on the graph a line that shows the car decelerating steadily to a stop from point D in 10 s. Mark the point w

Lady bird [3.3K]

Answer:

There is no deacceleration.

Explanation:

Let's check relation between velocity and acceleration

$\\ \rm\Rrightarrow a=\dfrac{dv}{dt}$

$\\ \rm\Rrightarrow a\propto dv$

So as velocity graph is going up acceleration is going up

Those flat lines on graph shows constant acceleration .

Curve lines up shows instantaneous acceleration.

If the graph is going down then it can be deacceleration .

Note :-No F is present in graph

5 0

2 years ago

Read 2 more answers

Indicate which of the following will elements will share the electrons and which one will transfer them?

DaniilM [7]

Answer:

b

Explanation:

8 0

3 years ago

A hot air balloon, when fully inflated, contains 2,800,000 Liter of air. If each mole of air occupies 22.4 L of at a temperature

emmainna [20.7K]

Answer:

1.44 atm

Explanation:

Step 1:

We'll begin by calculating the number of mole in 2,800,000 Liter of air.

I mole of air occupy 22.4L.

Therefore, Xmol of air will occupy 2800000L i.e

Xmol of air = 2800000/22.4

Xmol of air = 125000 moles

Step 2:

Determination of the pressure when the balloon is fully inflated .

This can be obtained as follow:

Number of mole (n) of air = 125000 moles

Volume (V) = 2800000 L

Temperature (T) = 120°C = 120°C + 273 = 393K

Gas constant (R) = 0.082atm.L/Kmol

Pressure (P) =.?

PV = nRT

Divide both side V

P= nRT/V

P= (125000x0.082x393) / 2800000

P = 1.44 atm

Therefore, the pressure of the air when the balloon is fully inflated is 1.44 atm

3 0

3 years ago

Calculate ΔH⁰298 (in kJ) for the process P(s) + 5/2 Cl2(g) → PCl5(g) from the following information.

Viefleur [7K]

Answer:

$\Delta H_{298}^{0}$ for the process is -375 kJ

Explanation:

Given reaction is a combination of the two given elementary steps.

Summation of change in standard enthalpy ( $\Delta H_{298}^{0}$ )of the two elementary reactions give $\Delta H_{298}^{0}$ of the reaction $P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g)$ .

$P(s)+\frac{3}{2}Cl_{2}(g)\rightarrow PCl_{3}(g)$ ...... $\Delta H_{1}=-287kJ$

$PCl_{3}(g)+Cl_{2}(g)\rightarrow PCl_{5}(g)$ ...... $\Delta H_{2}=-88kJ$

-----------------------------------------------------------------------------------------------------

$P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g)$

$\Delta H_{298}^{0}$ = $\Delta H_{1}+\Delta H_{2}=-287kJ-88kJ=-375kJ$

3 0

4 years ago