Answer:
aqueous acid is used as a reagent.
Explanation:
Addition of Grignard reagent in aldehyde and followed by the acidification give rise to the primary or secondary alcohol. when the formaldehyde is used than the primary alcohol is formed otherwise secondary alcohol is formed.
in this reaction we also use the aqueous acid for the acidification as a reagent. We add aqueous acid when ethanol is present. This is because ethanol is get converted in the presence of aqueous acid into the chloroethane.
The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.
The solubility of a substance in water is in accordance with the solubility rules. It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.
Now, we will consider each reaction individually to decode whether or not a precipitate is possible.
- In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.
- In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formed
- In the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g) + NaBr(aq) + H2O(l), a precipitate is not formed here.
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The solution has a concentration 20 mgr in each mL of the final solution.
To solve this problem, we need to know about concentration. The concentration formula can be defined as how much the mass per unit volume is. It can be written as
M = m/V
where M is concentration, m is mass of solute, V is the total volume of solution.
From the text we know that :
m = 10g
vsolvent = 45mL
vsolute = 5 mL
find the total volume (V)
V = vsolvent + vsolute
V = 45 + 5
V = 50mL
Then, find the concentration
M = m/V
M = 10gr / 50 mL
M = 1000 mgr / 50mL
M = 20 mgr / mL
Hence, the solution has a concentration 20 mgr in each mL of the final solution.
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