The formula of compound is LiClO4.3H2O
<em><u>calculation</u></em>
- <em><u> </u></em>find the mole of each element
that is moles for Li,Cl,O and that of H2O
- moles = % composition/ molar mass
For Li = 4.330/ 6.94 g/mol= 0.624 moles
Cl=22.10/35.5=0.623 moles
39.89/16 g/mol =2.493 moles
H20= 33.69/18 g/mol= 1.872 moles
- find the mole ratio by dividing each moles by smallest number of mole ( 0.624 moles)
that is for Li= 0.624/0.623= 1
Cl= 0.623/0.623=1
O = 2.493/0.623 =4
H2O= 1.872/0.623=3
<h3>Therefore the formula=LiClO4.3H2O</h3><h3 />
The Mitocondria is the powerhouse of the cells in plants
We are told that there are 1.55 x 10²³ molecules of Cl₂ and we need to calculate the mass of these molecules. We need to do several conversions. The easiest will be to convert the amount of molecules to the number of moles present. To do this, we need to use Avogadro's number which is 6.022 x 10²³ molecules/mole.
1.55 x 10²³ molecules / 6.022 x 10²³ molecules/mole = 0.257 moles Cl₂
Now that we have the moles of Cl₂ present, we can convert this value to a mass of Cl₂ by using the molecular mass of Cl₂. The molecular mass is 70.906 g/mol.
0.257 moles Cl₂ x 70.906 g/mol = 18.3 g Cl₂
Therefore, 1.55 x 10²³ molecules of Cl₂ will have a mass of 18.3 g.
Answer:
Carbon-14 or C-14
Explanation:
Since the isotope is a carbon isotope, it means the the atomic number of the isotope is 6.
The atomic number of an element is the proton number.
Therefore, the isotope has a proton number of 6
Now we need to obtain the mass number of isotope in order to write the symbol of the isotope. This is illustrated below:
Mass number = Proton +Neutron
Proton = 6
Neutron = 8
Mass number = 6 + 8
Mass number = 14
Therefore, the symbol of the isotope is carbon-14 or C-14
<span>For number
two, the equation is balanced. Na in the reactant side has one atom and also in
the product side. O has only one atom in the product and in the reactant. There
are 2H’s in the reactant and in the product side (present in H2O, the 2 in H
stands for 2 atoms of H). One atom of Cl is present in the reactant and product
side.</span>
For number
three, the reactants are NaOH-sodium hydroxide and HCl-hydrogen
chloride(hydrochloric acid). The products are NaCl-sodium chloride and
H2O-water.
