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maw [93]
1 year ago
10

If you run this reaction with 15 g of CuCl2 and 20 g NaNO3, what is the theoretical yield of NaCl?

Chemistry
1 answer:
Margaret [11]1 year ago
7 0

The theoretical yield of a substance is the amount of the mass that is calculated from stoichiometry. The mass of sodium chloride produced is 13.03 gms.

<h3>What is mass?</h3>

Mass of the substance is a multiplication of the molar mass and moles.

The balanced reaction is given as:

CuCl₂ + 2NaNO₃ ⇒ 2NaCl + Cu(NO₃)₂

Moles of copper chloride are calculated as: 15 ÷ 134.45 = 0.115 moles

Moles of sodium nitrate are calculated as: 20 ÷ 84.99 = 0.2353 moles

From the reaction, 1 mole of copper chloride gives 2 moles of sodium chloride so, 0.115 moles of copper chloride will produce 0.223 moles.

Similarly, 2 moles of sodium nitrate produce 2 moles of sodium chloride so, 0.2353 moles produce 0.4706 moles.

From this, it can be concluded that copper chloride is a limiting reagent and will be used to calculate the mass of NaCl.

Mass of NaCl is calculated as: Mass = 0.223 moles × 58.44 = 13.03 gms.

Therefore, 13.03 gms is the theoretical yield of sodium chloride.

Learn more about theoretical yield here:

brainly.com/question/1419024

#SPJ1

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D. The amount of heat required to increase the temperature of 1 g of a substance by 1 °C.

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The gram is constituted as a unit of mass, and the degree Celsius as a unit of temperature, therefore, the specific heat can be defined as the amount of heat required to increase the temperature of 1 g of a substance by 1 °C.

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Which arrangement of electrons is correct? Help please its timed!!!
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3 years ago
What is the molar mass of C4H10
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7 0
3 years ago
Some SbCl5 is allowed to dissociate into SbCl3 and Cl2 at 521 K. At equilibrium, [SbCl5] = 0.195 M, and [SbCl3] = [Cl2] = 6.98×1
Brilliant_brown [7]

Answer:

a) The equilibrium will shift in the right direction.

b) The new equilibrium concentrations after reestablishment of the equilibrium :

[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M

[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

Explanation:

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On increase in amount of reactant

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

If the reactant is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where more product formation is taking place. As the number of moles of SbCl_5 is  increasing .So, the equilibrium will shift in the right direction.

b)

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

Concentration of SbCl_5  = 0.195 M

Concentration of SbCl_3  = 6.98\times 10^{-2} M

Concentration of Cl_2  = 6.98\times 10^{-2} M

On adding more [SbCl_5 to 0.370 M at equilibrium :

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

Initially

0.370 M         6.98\times 10^{-2}M    

At equilibrium:

(0.370-x)M   (6.98\times 10^{-2}+x)M  

The equilibrium constant of the reaction  = K_c

K_c=2.50\times 10^{-2}

The equilibrium expression is given as:

K_c=\frac{[SbCl_3][Cl_2]}{[SbCl_5]}

2.50\times 10^{-2}=\frac{(6.98\times 10^{-2}+x)M\times (6.98\times 10^{-2}+x)M}{(0.370-x) M}

On solving for x:

x = 0.0233 M

The new equilibrium concentrations after reestablishment of the equilibrium :

[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M

[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

3 0
3 years ago
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Answer:

The answer is 3-Phenylpropanoic acid (see attached structure)

Explanation:

From spectral data:

3005 cm-1 ⇒ carboxylic acid (broad band)

1670 cm-1 ⇒ C=C

1603 cm-1 ⇒ Aromatic C-C bond

H NMR frequency at 2.6 ppm, singlet, ⇒ OH with no surrounding protons, possible deshielding  (clearer investigation of  spectrum would be expedient).

Hence, our C9H10O2 compound has an aromatic ring and carboxylic acid group attached to it.

7 0
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