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Luda [366]
3 years ago
11

How long it takes a 100 watt light bulb to use 10,000 J of electrical energy?​

Chemistry
1 answer:
vlabodo [156]3 years ago
7 0

Answer:

A 100-watt light bulb takes 100 seconds to use 10,000 J of electrical energy.

Explanation:

Power refers to the amount of work done (or energy consumed) per unit of time. It is usually measured in watts (W), which is equal to 1 Joules per second (\frac{J}{s})

So, by definition, to calculate the power consumed or supplied in a time interval the following expression is used:

P=\frac{W}{t}

where P is the power measured in Watts, W is the work measured in Joules, and t is the time measured in seconds.

In this case:

  • P=100 Watt
  • W= 10,000 J
  • t= ?

Replacing:

100 Watt=\frac{10,000 J}{t}

Solving:

t=\frac{10,000 J}{100 Watt}

t=100 seconds

<u><em> A 100-watt light bulb takes 100 seconds to use 10,000 J of electrical energy.</em></u>

<u><em></em></u>

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What are the 10 element​
maw [93]
  • hydrogen
  • oxygen
  • carbon
  • nitrogen
  • fluorine
  • silicone
  • boron
  • argon
  • cobalt
  • aluminum

hope it hepls✨

4 0
3 years ago
Draw the Lewis dot structure for RbIO2. Include all hydrogen atoms and nonbonding electrons. Show the formal charges of all atom
Rzqust [24]

Answer : The Lewis-dot structure of RbIO_2  is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, RbIO_2

As we know that rubidium has '1' valence electrons, iodine has '7' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in RbIO_2 = 1 + 7 + 2(6) = 20

As we know that RbIO_2  is an ionic compound because it is formed by the transfer of electron takes place from metal to non-metal element.

7 0
3 years ago
Cuántos mililitros de agua hay en 3 litros de una botella de naranjas y las solucion tiene una concentracion de 20% v/v
sertanlavr [38]

Respuesta:

2400 mL

Explicación:

Paso 1: Información dada

  • Volumen de solución: 3 L (3000 mL)
  • Concentración de naranja: 20 % v/v

Paso 2: Calcular el volumen de naranja

La concentración de naranja es de 20 % v/v, es decir, cada 100 mL de solución hay 20 mL de naranja.

3000 mL Sol × 20 mL Naranja/100 mL Solución = 600 mL Naranja

Paso 3: Calcular el volumn de agua

El volumen de soluciónes igual a la suma de los volúmenes de naranja y agua.

VSolución = VNaranja + VAgua

VAgua = VSolución - VNaranja

VAgua = 3000 mL - 600 mL = 2400 mL

8 0
3 years ago
A gas that was cooled to 200 Kelvin has a volume of 65.8 L. If its initial volume was 132.4 L, what was its initial temperature?
Mandarinka [93]

Answer:

Initial temperature, T1 = 99.4 Kelvin

Explanation:

<u>Given the following data;</u>

  • Initial volume, V1 = 65.8 Litres
  • Final temperature, T2 = 200 Kelvin
  • Final volume, V2 = 132.4 Litres

To find the initial temperature (T1), we would use Charles' law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles' law is given by the formula;

\frac {V}{T} = K

\frac {V_{1}}{T_{1}} = \frac {V_{2}}{T_{2}}

Making T1 as the subject formula, we have;

T_{1} = \frac {V_{1}T_{2}}{V_{2}}

Substituting the values into the formula, we have;

T_{1} = \frac {65.8 * 200}{132.4}

T_{1} = \frac {13160}{132.4}

<em>Initial temperature, T1 = 99.4 Kelvin</em>

6 0
3 years ago
Which interactions and processes contribute to the dissolution of ionic compounds in water?
Tanya [424]

Explanation:

Polarity is defined as the development of partial charges on the atoms of a molecule. In a water molecule, there are hydrogen and oxygen atoms.

Due to the difference in electronegativity of both hydrogen and oxygen atom there is development of partial positive charge on hydrogen atom and a partial negative charge on oxygen atom.  

So, when bond between hydrogen and oxygen will break down then it will form hydrogen ions (H^{+}) and oxygen ions (O^{2-}).

Ion-dipole interactions are defined as the interactions that occur when an ion interacts with the dipole of a molecule.

When an electron is added to a neutral atom to convert it into a negative ion then the amount of change taking place in its energy is known as electron affinity.

So, oxygen atom has an affinity towards cations and hydrogen atom has an affinity for anions.

Thus, we can conclude that following interactions and processes contribute to the dissolution of ionic compounds in water:

1. Affinity of oxygen towards cations

2. Ion–dipole interactions

4. Hydration

6. Affinity of hydrogen towards anions

3 0
3 years ago
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