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malfutka [58]
3 years ago
10

A car is traveling at a speed of 25 meters per second what is the cars speed in kilometers per hour how many kilometers will the

car travel in 2 hours ?
Mathematics
1 answer:
Likurg_2 [28]3 years ago
7 0

Answer:

  • 90 km/h
  • 180 km

Step-by-step explanation:

There are 1000 m in 1 km, and 3600 s in 1 h, so the speed conversion is ...

  \dfrac{25\,m}{s}\cdot\dfrac{1\,km}{1000\,m}\cdot\dfrac{3600\,s}{1\,h}=\dfrac{90\,km}{h}

The car's speed is 90 km/h.

__

In 2 hours, the car will travel ...

  distance = speed · time = (90 km/h)(2 h) = 180 km

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2(x-+2)+4=6x-4(-1+x)
sertanlavr [38]

2x-4+4=6x+4-4x

2x=2x+4

c there is no solution

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3 years ago
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If there are 420 students surveyed, which equation can be used to find the number of students s who prefer rap? Pop: 5/8 Jazz: 1
Aleksandr [31]

Answer:

B. s=\dfrac{1}{4}\times420

Step-by-step explanation:

Total number of students surveyed = 420

Of which only \dfrac{1}{4} prefer rap.

So, the number of people who like rap is the product of the fraction of people who prefer rap and the total number of students.

\text{Number of students who prefer rap}=s=\dfrac{1}{4}\times420\\\Rightarrow s=105

The number of students that prefer rap is 105

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3 0
3 years ago
Paul has 15% of his gross pay directly deposited into a mutual fund account each month. If $630 is deposited each month, what is
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4 0
3 years ago
The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
3 years ago
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I am Lyosha [343]

Answer:

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