Answer:
The Electric Force on Negative Charge is 2.968 N
Explanation:
charge on each corner, q = 2.38 micro coulomb
Side of square, a = 75.2 cm
Coulombic constant, K = 8.98755 x 10^9 Nm²/C²
sides of the square are A,B,C and D
and all sides of a square are equal so
AB = BC = CD = DA = 75.2 cm = 0.752 m
Diagonal, AC = BD = 1.414 x 0.752 = 1.06 m
Electric field at D due to charge at A
EA= Kq÷AB^2
= 8.98755×10^9 × 9.87×10^-6 ÷ 0.752^2
EA= 156863.82 N/C
Similarly Electric field at D due to charge C
EC=Kq÷CD^2
= 8.98755×10^9 ×9.87×10^-6 ÷ 0.752^2
EC= 156863.82 N/C
Electric field at D due to charge at BB
EB=Kq÷BD^2
EB=8.98755×10^9 × 9.87×10^-6 ÷ 1.06^2
EB=78949.01 N/C
Resolve the compoents
Ex = EA + EB cos 45
Ex = 156863.82 + 78949.01 x 0.707
Ex = 212689.2 N/C
Ey = EC + EB Sin 45
Ey = 156863.82 + 78949.01 x 0.707
Ey = 212689.2 N/C
The resultant electric field is
E = 1.414 x 212689.2 = 300787.95 N/C
the electric force on the negative charge is
F = q x E
F = 9.87 x 10^-6 x 300787.95
F = 2.968 N
