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s344n2d4d5 [400]
3 years ago
8

As the wavelength increases, the frequency (2 points) decreases and energy decreases. increases and energy increases. decreases

and energy increases. increases and energy decreases
Physics
2 answers:
lora16 [44]3 years ago
4 0

Answer:

I TOOK THE TEST! the answer is INCREASES AND ENERGY INCREASES!

frozen [14]3 years ago
3 0
Bohr's equation for the change in energy is
\Delta E= \frac{hc}{\lambda}
where
h = Planck's constant
c == the velocity of light
λ = wavelength.

The velocity is related to wavelength and frequency, f, by
c = fλ

Let us examine the given answers on the basis of the given equations.

a. As λ increases, f decreases and ΔE decreases.
     TRUE

b. As λ increases, f increases and ΔE increases.
    FALSE

c. As λ increases, f increases and ΔE decreases.
    FALSE

Answer: 
As the wavelength increases, the frequency decreases and energy decreases.

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A motorcycle stunt driver zooms off the end of a cliff at a speed of 30 meters per second. If he lands after 0.75 seconds, what
marissa [1.9K]
u = 30ms^{-1}
\\t = 0.75s
\\a = 9.8ms^{-2} (Gravity)
\\s = ?

s = ut +  \frac{1}{2}at^2
\\s = (30)(0.75)+ \frac{1}{2}(9.8)(0.75)^2
\\s = 22.5 + 2.75625
\\s = 25.25625

<u>s = 25.3 m (3 sf)</u>

5 0
2 years ago
Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1050 kg and was approaching at
Soloha48 [4]

Answer:

v = 11.0 m/s at 198.6° (18.6° south of west)

ΔKE = -145 kJ

Explanation:

I assume you want to find the final velocity and the change in kinetic energy.

Take east to be +x and north to be +y.

Momentum is conserved in the x direction:

(1050 kg) (0 m/s) + (750 kg) (-25.0 m/s) = (1050 kg + 750 kg) vₓ

vₓ = -10.4 m/s

Momentum is conserved in the y direction:

(1050 kg) (-6.00 m/s) + (750 kg) (0 m/s) = (1050 kg + 750 kg) vᵧ

vᵧ = -3.50 m/s

The magnitude of the final velocity is:

v² = (-10.4 m/s)² + (-3.50 m/s)²

v = 11.0 m/s

The direction of the final velocity is:

θ = atan(-3.50 m/s / -10.4 m/s)

θ = 198.6°

The initial kinetic energy is:

KE₀ = ½ (1050 kg) (6.00 m/s)² + ½ (750 kg) (25.0 m/s)²

KE₀ = 253,275 J

The final kinetic energy is:

KE = ½ (1800 kg) (11.0 m/s)²

KE = 108,682 J

The change in kinetic energy is:

ΔKE = 108,682 J − 253,275 J

ΔKE ≈ -145,000 J

7 0
3 years ago
When a driver presses the brake pedal, his car can stop with an acceleration of 5.4 m/s2. How far will the car travel while comi
notsponge [240]
Given:\\a=5.4 \frac{m}{s^2}  \\v_0= 25\frac{m}{s} \\\\Find:\\s=?\\\\Solution:\\\\s=v_0t- \frac{at^2}{2} \\\\a= \frac{\Delta v}{t} \\\\v_e=0\Rightarrow \Delta v=v_0\\\\t= \frac{v_0}{a} \\\\s= \frac{v_0^2}{a} - \frac{v_0^2}{2a} =\frac{v_0^2}{2a} \\\\s= \frac{ (25\frac{m}{s})2 }{2\cdot 5.4 \frac{m}{s^2} } \approx 57.9m\\\\C\rightarrow Correct\;answer
3 0
3 years ago
The photograph shows matter changing states. Which statement best describes what happens to the particles of matter during this
AfilCa [17]
Its a tightly-packed particles gain energy, allowing them to move more freely.
6 0
2 years ago
Read 2 more answers
Find B when θ=35, E=10V, t=5, N=250, A=1.20m^2
givi [52]

Answer:

its most definitely c. trust me

Explanation:

3 0
2 years ago
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