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Stella [2.4K]
3 years ago
10

E TRUE OR FALSE: Write the word TRUE if the statement is correct, and FALSE if it is not. (3 points each). Write your answer on

a separate sheet of paper. 1. Most EM waves has the same speed. 2. EM waves travel at the speed of 4x108 m/s. 3. Electromagnetic waves are transverse waves consisting of changing electric fields and changing magnetic fields. 4. Electromagnetic waves transfer energy through a vacuum. 5. A wave is a disturbance that transfers energy .what the answer?
​
Physics
1 answer:
worty [1.4K]3 years ago
8 0

Answer:

TRUE

FALSE

TRUE

TRUE

TRUE

TRUE

Explanation:

1. Most EM waves has the same speed. True

2. EM waves travel at the speed of 4x108 m/s. False

3. Electromagnetic waves are transverse waves consisting of changing electric fields and changing magnetic fields. True

4. Electromagnetic waves transfer energy through a vacuum. True

5. A wave is a disturbance that transfers energy. True

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An unstable atomic nucleus of mass 1.58 10-26 kg initially at rest disintegrates into three particles. One of the particles, of
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Answer:

a The velocity of the third particle is v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s

b The total kinetic energy increase E = 6.50 *10^{-13} J

Explanation:

To solve this question we are going to be using the concept of conservation of momentum which is mathematically represented as

            m_1v_1 +m_2v_2 +m_3v_3 = 0

From the question

        Mass of  unstable atomic nucleus m_0= 1.58 *10^{-26} kg

        Mass of  x-axis particle m_1 = 8.44* 10^{-27} kg

        Velocity of x-axis particle v_ 1 =  4.00* 10^6 m/s

         Mass of  y-axis particle  m_2 =5.20* 10^{-27} kg

            Velocity of y-axis particle  v_2 = 6.00 *10^6 m/s

 Since the initial mass is known we can obtain the mass of the third particle  

 Using the conservation of mass mathematical expression

                m_3 = m_0 - (m_1 +m_2)

                  m_3 = 1.58 *10^{-26}  - ( 8.44* 10^{-27} + 5.20* 10^-27)

                        = 2.16 *10 ^{-27}kg

Using the mathematical expression above for conservation of momentum

               (8.44 * 10^{-27})( 4.00* 10^6i) + (5.20 *10^{-27})(6.00* 10^6j) +(2.16*0^{-27})v_3 =0

            v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s

The above is the vector solution now to obtain the value in numeric form we evaluate the magnitude of the vector

         Mag  = \sqrt{(15.629*10^6)^2 +(14.45*10^6)^2}

                = 21.285*10^6 \ m/s

To obtain the total increase in  kinetic energy which is mathematically represented as

         E = \frac{1}{2}m_1v_1 +  \frac{1}{2}m_2v_2 + \frac{1}{2} m_3 v_3

         E =\frac{1}{2} [(5.20*10^{-27})(6.0*0^{6})^2 + (8.44*10^{-27})(4.00*10^6)^2+\\\\(2.16*10^{-27})(21.285*10^6)^2]

              = 6.50 *10^{-13} J

5 0
3 years ago
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