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VARVARA [1.3K]
2 years ago
14

What is the point-slope form of a line that has a slope of 5 and passes through the point (3,-4)? y-3=5[x-(-4)] -4-y₁ = 5(3-x₁)

y-(-4)=3(x - 5) y-(-4)= 5(x-3)​
Mathematics
1 answer:
Sedaia [141]2 years ago
6 0

Answer:

y -(-4)= 5(x -3)

Step-by-step explanation:

The point-slope form of a line is given by y -y₁= m(x -x₁), where m is the slope.

<u>Given</u>

Slope, m= 5

(x₁, y₁)= (3, -4)

Substitute the given information into the equation:

y -(-4)= 5(x -3)

The 4th option is thus correct.

_____

Simplifying the equation:

y +4= 5(x -3)

Additional:

For a similar question on point-slope form, do check out the following!

  • brainly.com/question/837699

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D. One

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<h3>Answer:  60 units</h3>

=====================================================

Explanation:

The similar red marks on the angles tell us those angles are congruent. So they are the same measure.

The sides opposite those congruent angles are the same length. This means AC = BC. This triangle is isosceles.

--------------

Solve for x

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5x-8 = 2x+7 .... substitution

5x-8-2x = 7 ... subtract 2x from both sides

5x-2x = 7+8 ..... add 8 to both sides

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x = 15/3 ... divide both sides by 3

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---------------

Use that x value to compute each side length

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----------------

The last step is to add up all the side lengths to get the perimeter

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