All categories

2 years ago

Hello,help me with this out please i need it hurry but please ensure your answer is correct..I attach here with my question.

Physics

1 answer:

lilavasa [31]2 years ago

7 0

Answer:

.409 N

Explanation:

For this to balance, the moments around the fulcrum must sum to zero.

On the left you have .21 ( is that down? I will assume it is)

Counterclockwise moments :

.21 * 40 + 1.0 * 20

Clockwise moments :

.5 * 20 + F * 45

these moments must equal each other

.21*40 + 1 *20 = .5 * 20 + F * 45

F = .409 N

You might be interested in

A freight train has a mass of 1.5 X 10^7 kg. If the

Elena L [17]

Answer:

t=444.4s

Explanation:

m=1.5*10^7 kg

F=7.5*10^5 N

v=80km/h*(1h/3600s)*(1000m/1km)=22.22m/s

<u>Second Newton's Law:</u>

F=ma

a=F/m=7.5*10^5/(1.5*10^7)=0.05m/s^2

<u>Kinematics equation:</u>

vf=vo+at=at

vo: initial velocity equal zero

t=vf/a=22.22/0.05=444.4s

4 0

3 years ago

Mary slides down a snow-covered hill on a large piece of cardboard and then slides across a frozen pond at a constant velocity o

Sophie [7]

Explanation is in the file

tinyurl.com/wtjfavyw

8 0

4 years ago

What are the signs of the angular velocity ω and angular acceleration α of the pulley in case (a)? by convention, clockwise rota

schepotkina [342]

Everything which rotates in the direction of clock is taken as negative and opposite to clock is taken as positive. It is a sign convention.

5 0

4 years ago

3.5 kJ of heat are added to a 3.4 kg block of ice at temperature of -7.6oC. Suppose the amount of heat added to the ice block is

Bond [772]

Answer:

Explanation:

If the energy is doubled, the mass must be doubled (increased by a factor of 2) in order for the temperature effect to remain the same.

Heat capacity is measured in units of J/(kg·°C), so the ratio will remain constant if mass varies directly with amount of heat.

7 0

3 years ago

When you push a 1.70 kg book resting on a tabletop it takes 2.60 N to start the book sliding. Once it is sliding, however, it ta

bezimeni [28]

Answer:

Coefficient of static friction ,μs = 0.15

Coefficient of kinetic friction ,μk = 0.089

Explanation:

Given that

m = 1.7 kg

Static friction :

The force required to start the motion F= 2.6 N

We know that when book is in rest condition then static friction force act on it.

We know that the maximum value of the static friction force

fr = μ m g

At limiting condition

F= fr

2.6 = μ m g

2.6 = μ x 1.7 x 9.81

$\mu=\dfrac{2.6}{1.7\times 9.81}$

μ = 0.15

Kinetic friction :

F= 1.5 N

When the book is in moving condition then kinetic friction force act on it.

We know that the maximum value of the kinetic friction force

fr = μ m g

F= fr

= μ m g

1.5 = μ x 1.7 x 9.81

$\mu=\dfrac{1.5}{1.7\times 9.81}$

μ = 0.089

Coefficient of static friction ,μs = 0.15

Coefficient of kinetic friction ,μk = 0.089

7 0

3 years ago

Read 2 more answers