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34kurt
4 years ago
7

PLEASE HELP ME!!!!!!!

Physics
1 answer:
melamori03 [73]4 years ago
6 0

<em><u>This</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>can</u></em><em><u> </u></em><em><u>do</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>boy</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>girl</u></em><em><u> </u></em>

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A girl weighing 600 N steps on a bathroom scale that contains a stiff spring. In equilibrium, the spring is compressed 1.0 cm un
8_murik_8 [283]

Answer:

The spring constant is 60,000 N

The total work done on it during the compression is 3 J

Explanation:

Given;

weight of the girl, W = 600 N

compression of the spring, x = 1 cm = 0.01 m

To determine the spring constant, we apply hook's law;

F = kx

where;

F is applied force or weight on the spring

k is the spring constant

x is the compression of the spring

k = F / x

k = 600 / 0.01

k = 60,000 N

The total work done on the spring = elastic potential energy of the spring, U;

U = ¹/₂kx²

U = ¹/₂(60000)(0.01)²

U = 3 J

Thus, the total work done on it during the compression is 3 J

3 0
3 years ago
The product PV, where P and V represent pressure and volume respectively, is a unit for which?
Gekata [30.6K]
I believe the answer is D: Work. PV is the formula for work.
6 0
3 years ago
Read 2 more answers
A batter strikes a baseball of mass 0.15 kg with a force of 18 kn. whats the acceleration of the baseball? 9.8 m/s^2 120000 m/s^
bazaltina [42]
To calculate the acceleration of the baseball, we use the expression F = ma where F is the force, m is the mass of the object and a is the acceleration. We calculate as follows:

F = ma
18000 = 0.15a
a = 120000 <span>m/s^2 ------> SECOND OPTION</span>
3 0
3 years ago
1. A 75 kg rock climber hangs from a cliff.
aliina [53]

The free body diagram of the rock comprises the tension on the rope acting upwards and the weight of the rock acting downwards.

The tension on the supporting rope is 735 N.

The given parameters;

  • <em>mass of the rock, m = 75 kg</em>

(a) The free body diagram of the rock is presented as follows;

                                                 ↑ T

                                                 Ο

                                                 ↓ W

Where;

<em>T is the tension on the supporting rope</em>

<em>W is the weight of the rock</em>

(b) The tension on the rope is calculated as follows;

T = W

T = mg

T = 75 x 9.8

T = 735 N

Thus, the free body diagram of the rock comprises the tension on the rope acting upwards and the weight of the rock acting downwards. The tension on the supporting rope is 735 N.

Learn more here: brainly.com/question/11599933

6 0
3 years ago
Why is the moon's umbra much smaller during a solar eclipse?
Stolb23 [73]

Answer:

the sun is larger than the moon so it creates a shadow

7 0
3 years ago
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