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2 years ago

6

How much does the gravitational force of attraction change between two asteroids if the two asteroids drift three times closer t

ogether?

1 answer:

Katen [24]2 years ago

6 0

Answer:

Increase 9 times

Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

$F_G = G\frac{M_1M_2}{R^2}$

where $G =6.67408 \times 10^{-11} m^3/kgs^2$ is the gravitational constant. $M_1, M_2$ is the masses of the 2 objects. and R is the distance between them.

Since the force is inversely proportional to the distance squared, if it is reduced by 3 times, the gravitational force between them would increase by $3^2 = 9$ times

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2 years ago

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Two cello strings, with the same tension and length, are played simultaneously. Their fundamental frequencies produce audible be

qwelly [4]

Explanation:

Let f₁ is the fundamental frequency, $f_1=8\ Hz$

Lower pitch frequency, $f_2=220\ Hz$

Fundamental frequency is, $f_1=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu_1}}$ .....(1)

Lower frequency is, $f_2=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu_2}}$ ..............(2)

Dividing equation (1) and (2) as :

$\dfrac{f_1}{f_2}=\sqrt{\dfrac{\mu_2}{\mu_1}}$

$\dfrac{\mu_2}{\mu_1}=(\dfrac{f_1}{f_2})^2$

$\dfrac{\mu_2}{\mu_1}=(\dfrac{8}{220})^2$

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So, the ratio of linear mass density μ of the string with the higher pitch to that of the string with the lower pitch is 0.00132. Hence, this is the required solution.

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2 years ago

When responding to sound, the human eardrum vibrates about its equilibrium position. suppose an eardrum is vibrating with an amp

vodomira [7]

745.92 hz (b)
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2 years ago

Twin A makes a one way trip at 0.6c to a star 12 light years away while twin B stays on Earth. Each twin sends the other a signa

hram777 [196]

Answer:

8 signals received by twin A during the trip.

Explanation:

Given that,

Distance = 12 light year

Speed = 0.6 c

Time = 1 year

We need to calculate the time by A

Using formula of time

$T=t\sqrt{\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}}$

Put the value into the formula

$T=1\sqrt{\dfrac{1+0.6}{1-0.6}}$

$T=2\ years$

Similarly,

The expression for distance cover by A

$D=d\sqrt{1-\dfrac{v^2}{c^2}}$

$D=12\sqrt{1-(0.6)^2}$

$D=9.6\ ly$

We need to calculate the time

Using formula of time

$t=\dfrac{D}{v}$

$t=\dfrac{9.6}{0.6}$

$t=16\ years$

We need to calculate the signals received by twin A

Using formula for number of signals

$n=\dfrac{t}{T}$

Put the value into the formula

$n=\dfrac{16}{2}$

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Hence, 8 signals received by twin A during the trip.

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3 years ago

How many electrons are in the outer energy level of an atom of carbon

xz_007 [3.2K]

Answer:

4 electrons

Explanation:

Carbon, is the group 14 element, with four electrons in its outer shell. Carbon always shares electrons to reach a complete valence shell, making bonds with other atoms.

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3 years ago