Answer:
(B) 13.9 m
(C) 1.06 s
Explanation:
Given:
v₀ = 5.2 m/s
y₀ = 12.5 m
(A) The acceleration in free fall is -9.8 m/s².
(B) At maximum height, v = 0 m/s.
v² = v₀² + 2aΔy
(0 m/s)² = (5.2 m/s)² + 2 (-9.8 m/s²) (y − 12.5 m)
y = 13.9 m
(C) When the shell returns to a height of 12.5 m, the final velocity v is -5.2 m/s.
v = at + v₀
-5.2 m/s = (-9.8 m/s²) t + 5.2 m/s
t = 1.06 s
A compound is a substance that consists of two or more elements, which is chemically combined, meaning that it could only be split by chemical means.
Examples:-
- NaCl is salt, chemically combined of Sodium and Chloride.
- H2O is water, chemically combined of Hydrogen and oxygen.
Answer:
0.799 m/s if air resistance is negligible.
Explanation:
For how long is the ball in the air?
Acceleration is constant. The change in the ball's height depends on the square of the time:
,
where
- is the change in the ball's height.
- is the acceleration due to gravity.
- is the time for which the ball is in the air.
- is the initial vertical velocity of the ball.
- The height of the ball decreases, so this value should be the opposite of the height of the table relative to the ground. .
- Gravity pulls objects toward the earth, so is also negative. near the surface of the earth.
- Assume that the table is flat. The vertical velocity of the ball will be zero until it falls off the edge. As a result, .
Solve for .
;
;
;
.
What's the initial horizontal velocity of the ball?
- Horizontal displacement of the ball: ;
- Time taken:
Assume that air resistance is negligible. Only gravity is acting on the ball when it falls from the tabletop. The horizontal velocity of the ball will not change while the ball is in the air. In other words, the ball will move away from the table at the same speed at which it rolls towards the edge.
.
Both values from the question come with 3 significant figures. Keep more significant figures than that during the calculation and round the final result to the same number of significant figures.
Answer:
metals,nonmetals, and inert gases
Explanation:
Answer:
The elastic potential energy of the spring change during this process is 21.6 J.
Explanation:
Given that,
Spring constant of the spring,
It extends 6 cm away from its equilibrium position.
We need to find the elastic potential energy of the spring change during this process. The elastic potential energy of the spring is given by the formula as follows :
So, the elastic potential energy of the spring change during this process is 21.6 J.