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3 years ago

6

How much does the gravitational force of attraction change between two asteroids if the two asteroids drift three times closer t

ogether?

1 answer:

Katen [24]3 years ago

6 0

Answer:

Increase 9 times

Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

$F_G = G\frac{M_1M_2}{R^2}$

where $G =6.67408 \times 10^{-11} m^3/kgs^2$ is the gravitational constant. $M_1, M_2$ is the masses of the 2 objects. and R is the distance between them.

Since the force is inversely proportional to the distance squared, if it is reduced by 3 times, the gravitational force between them would increase by $3^2 = 9$ times

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An MRI technician moves his hand from a region of very low magnetic field strength into an MRI scanner's 2.00 T field with his f

makkiz [27]

Answer:

2.62 A

Explanation:

B = 2 T, Diameter = 2.5 cm , radius, r = 0.0125 m, t = 0.45 s, r = 0.01 ohm

Induced emf, e = rate of change of magnetic flux

e = A x dB / dt = 3.14 x (0.0125)^2 x 2 / 0.45

e = 0.026 V

induced current, i = e / R = 0.026 / 0.01 = 2.62 A

7 0

3 years ago

You take the mass of the object 400 grams then what do you predict the force needed to move the object at a constant acceleratio

Oksanka [162]

Answer:

Below

Explanation:

To find the force needed to move an object, you can use this formula :

force = (mass)(acceleration)

Plugging our values in...

force = (400g)(3 m/s^2)

= 1,200 Newtons

We can see how this works for the previous answers :

force = (100g)(3 m/s^2)

= 300 Newtons and so on....

Hope this helps! Best of luck <3

6 0

3 years ago

A stone is dropped at t = 0. A second stone, with 6 times the mass of the first, is dropped from the same point at t = 59 ms. (a

xxTIMURxx [149]

Answer: $y_{com}=0.707 m$

$v_{com}=3.713 m/s$

Explanation:

Given

first stone mass is m

second stone mass is 6 m

distance traveled by first stone in 430 ms

$y_1=ut+\frac{at^2}{2}$

$y_1=0+\frac{g(0.43)^2}{2}$

$y_1=0.9069 m$

Distance traveled by stone 2 in t=430-59=371 ms

$y_2=ut+\frac{at^2}{2}$

$y_2=0+\frac{g(0.0.371)^2}{2}$

$y_2=0.674 m$

velocity of first stone after t=0.43 s

$v_1=u+at$

$v_1=0+9.8\times 0.43=4.214 m/s$

velocity of second stone after t=0.371 s

$v_2=u+at$

$v_2=0+9.8\times 0.371=3.63 m/s$

Position of Center of mass of system

$y=\frac{y_1m_1+y_2m_2}{m_1+m_2}$

$y=\frac{0.9069\times m+0.674\times 6m}{m+6m}$

$y=\frac{4.95m}{7m}=0.707 m$

Velocity of COM

$v_{com}=\frac{v_1m_1+v_2m_2}{m_1+m_2}$

$v_{com}=\frac{4.214\times m+3.63\times 6m}{m+6m}$

$v_{com}=3.713 m/s$

6 0

4 years ago

Which statements best describe displacement? Check all that apply.

xxMikexx [17]

Answer:

the last one, the third one, and the first one.

8 0

3 years ago

Read 2 more answers

Ideal gases are often studied at standard ambient temperature and pressure (satp). The international union of pure and applied c

11Alexandr11 [23.1K]

This problem provides information about the pressure and temperature ideal gases are studied at. The answer to the questions are that all molecules have the same density, 2.43x10²⁵ mol/m³ and 2.43x10¹⁹ mol/cm³.

<h3>Idela gases</h3>

In science, we can start studying gases with the concept of ideal gas, as they do not collide one to another and are assumed to be perfect spheres with no relevant interactions.

In such a way, one can conclude that the <u>number density of all ideal gasses at SATP is the same</u>, as they are assumed to be perfect spheres with equal volumes per molecule.

Moreover, when calculating the number of molecules per cubic meter, one must use the ideal gas equation as:

$PV=nRT\\\\\frac{N}{V}= \frac{P*N_A}{RT}$

And plug in the numbers we are given:

$\frac{N}{V}= \frac{100kPa*\frac{1000Pa}{1kPa}*6.022x10^{23}molec/mol}{8.314\frac{Pa*m^3}{mol*K}*298K}=2.43x10^{25}molec/m^3$

Lastly, we can calculate the molecules per cubic centimeter by performing the following conversion:

$2.43x10^{25}\frac{molec}{m^3}*(\frac{1m}{100cm} )^3\\ \\=2.43x10^{19}\frac{molec}{cm^3}$

Learn more about ideal gases: brainly.com/question/26450101

5 0

3 years ago