It is very important to note down all the details that are given in the question. Based on these details the answer can be derived.
Initial velocity of the car (V1) = 0 meters/second
Final velocity of the car (V2) = 40 meters/second
Initial time (T1) = 0 Second
Final time (T2) = 60 seconds (In this case we have converted 1 minute into 60 seconds for the ease of calculation.
Then
Average acceleration = (V2 - V1)/ (T2 - T1) m/s^2
= (40 - 0)/(60 - 0) m/s^2
= 40/60 m/s^2
= 2/3 m/s^2
= 0.67 m/s^2
So the average acceleration of the car is 0.67 meters/second square.
Chemical bonds. These bonds form as a result of the sharing or exchange of electrons between the atoms
Molecular formula for ammonia is
NH3... Structural formula for ammonia is see the pic. 107.3°
is the bond angle between H-N-H. A pair of dots above N are called lone pair of electrons and are responsible for the basicity of NH3.
Answer:
![d>10.72896\ m](https://tex.z-dn.net/?f=d%3E10.72896%5C%20m)
Explanation:
Given:
- initial speed of the car,
![u=30\ mph=13.4112\ m.s^{-1}](https://tex.z-dn.net/?f=u%3D30%5C%20mph%3D13.4112%5C%20m.s%5E%7B-1%7D)
- time taken to realize the need of braking,
![t=0.8\ s](https://tex.z-dn.net/?f=t%3D0.8%5C%20s)
<u>Distance travelled during the time span:</u>
![d=u.t](https://tex.z-dn.net/?f=d%3Du.t)
![d=13.4112\times 0.8](https://tex.z-dn.net/?f=d%3D13.4112%5Ctimes%200.8)
![d=10.72896\ m](https://tex.z-dn.net/?f=d%3D10.72896%5C%20m)
Actually the distance travelled before stopping the car will be greater than this distance, because after the application of brakes the car will take some time to come to rest.