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vodomira [7]
3 years ago
11

What happens when a star exhausts its core hydrogen supply?

Physics
1 answer:
Allushta [10]3 years ago
6 0

Answer:

It becomes a giant or supergiant.

Explanation:

Once all the hydrogen supply is gone, fusion of hydrogen into helium stops. The core starts to contract and liberates energy, which heats the superior layer until it becomes hot enough to start the fusion of hydrogen into helium.

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I NEED THIS ANSWER TODAY PLEASE HELP ME
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The answer is "B" - If there are no windows then there will be no light coming in, and therefore you don't have to worry about what time of day you do the experiment at.

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The pictures shows what a student observed when he looked through a hand lens at a penny.
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The answer is A. Refracted
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Why is it important that home circuits are wired with parallel circuits?
Arlecino [84]

Answer:

Parallel circuits are used in homes because the loads can be operated independently of each other. That means that you can have an electrical item turned on and running without needing to have all of the other loads on and running as well.

5 0
3 years ago
Why is it sometimes difficult for scientists to identify a a fold or fault?
Sauron [17]

Folds and faults are difficult to identify because they occur in the interior of rocks and also due to the dense nature of the materials.

<h3>What are faults and folds?</h3>

Faults are lines of weakness are present in materials dues to uneven positioning of the particles of the material.

Folds occurs when infolds occur in materials.

Faults and folds usually occur in rocks.

Folds and faults are difficult to identify because they occur internally and also due to the dense nature of the materials.

Learn more about faults and folds at: brainly.com/question/14240712

4 0
2 years ago
Jonah is trying to move his 22-kg desk by pushing on it with a force of 130 N, but his brother is leaning on it with a downward
Dafna11 [192]

Answer:

0.54

Explanation:

Draw a free body diagram.  There are 5 forces on the desk:

Weight force mg pulling down

Applied force 24 N pushing down

Normal force Fn pushing up

Applied force 130 N pushing right

Friction force Fnμ pushing left

Sum of the forces in the y direction:

∑F = ma

Fn − mg − 24 = 0

Fn = mg + 24

Fn = (22)(9.8) + 24

Fn = 240

Sum of the forces in the x direction:

∑F = ma

130 − Fnμ = 0

Fnμ = 130

μ = 130 / Fn

μ = 130 / 240

μ = 0.54

6 0
3 years ago
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